For the first one it is x= (y+3)/4
<span>Rigid motion does not change the shape of an object. if you move an object to another place, you can think of it as a new object (a copy) at the new position and it will be congruent to the object at the original position. or, if two objects are congruent, you can move one object so it lies on top of the other, showing they are congruent.</span>
Let's treat the speed in one hour as a variable.
We can say that 1500=12.5x
Divide by 12.5
1500/12.5 = x
x = 120
120 mph is your answer.
<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
Answer:
Correct answer: Fourth answer As = 73.06 m²
Step-by-step explanation:
Given:
Radius of circle R = 16 m
Angle of circular section θ = π/2
The area of a segment is obtained by subtracting from the area of the circular section the area of an right-angled right triangle.
We calculate the circular section area using the formula:
Acs = R²· θ / 2
We calculate the area of an right-angled right triangle using the formula:
Art = R² / 2
The area of a segment is:
As = Acs - Art = R²· θ / 2 - R² / 2 = R² / 2 ( θ - 1)
As = 16² / 2 · ( π/2 - 1) = 256 / 2 · ( 1.570796 - 1) = 128 · 0.570796 = 73.06 m²
As = 73.06 m²
God is with you!!!
