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SSSSS [86.1K]
2 years ago
11

Rewrite the expression 4×12 two different ways to show the distributive property over both addition and subtraction

Mathematics
1 answer:
Alex787 [66]2 years ago
5 0
For addition: 12+12+12+12
Subtraction: not sure sry

:) hope this helps tho
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A basketball team is down by 2 points with only a few seconds remaining in the game. There is a 60% chance that the team will be
Mashcka [7]

Answer:

This means that the coach should have the team going for the 2 point shot. There is a 36% probability of making the 2 point shot and winning overtime.

Step-by-step explanation:

We have these following probabilities:

A 60% probability of tying the game on a 2 point shot. In this case, the game goes to overtime, in which the team has a 60% probability of winning.

A 30% probability of making the 3 point shot and winning.

What should the coach do, go for the 2 point shot or the 3 point shot?

In which case the team has a higher probability of winning?

The team has:

A 60% probability of tying the game on a 2 point shot. In this case, the game goes to overtime, in which the team has a 60% probability of winning. So, going for the 2 point shot, the team has a 0.6*0.6 = 0.36 = 36% probability of winning.

Going for the 3 point shot, the team has a 30% probability of winning.

This means that the coach should have the team going for the 2 point shot. There is a 36% probability of making the 2 point shot and winning overtime.

7 0
3 years ago
Points giveaway points giveaway points giveaway
Nina [5.8K]

Answer:

You are awesome!

Step-by-step explanation:

No need for that. :)

4 0
3 years ago
Read 2 more answers
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
2 years ago
University theater sold $525 tickets for a play. Tickets cost &amp;21 per adult and $12 per senior citizen. If total receipts we
Kamila [148]
620.25 u calculate 7443 and divide that by 12
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3 years ago
Sam is flying a kite. The length of the kite string is 80 meters, and it makes an angle of 75 with the ground. The height of the
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You don't say if the answer needs to be rounded 
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 see attached picture for solution:

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3 years ago
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