Question

(-8,-2) and (-4,6) write a equation

Answer 1

The equation of line passing through (-8, -2) and (-4, 6) is y = 2x + 14

Solution:

Given that  

Line is passing through point (− 8 ,− 2) and ( -4 , 6 )

Equation of line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by:

$y-y_{1}=\frac{\left(y_{2}-y_{1}\right)}{\left(x_{2}-x_{1}\right)}\left(x-x_{1}\right)$   ----- eqn 1

$\text { In our case } x_{1}=-8, y_{1}=-2, x_{2}=-4, y_{2}=6$

Substituting given value in (1) we get

$\begin{array}{l}{y-(-2)=\frac{(6-(-2))}{(-4-(-8))}(x-(-8))} \\\\ {=>y+2=\frac{8}{4}(x+8)} \\\\ {=>y+2=2(x+8)} \\\\ {=>y+2=2 x+16} \\\\ {=>-2 x+y=14}\end{array}$

Thus the required equation of line is y = 2x + 14