Answer:
The step to take to avoid fraction is to solve for y in equation 2
Step-by-step explanation:
Given
-9x+ 4y =- 10
-9x+ 3y = 3
Required:
Step for solving using substitution (avoiding fraction)
Let -9x+ 4y =- 10 represent equation 1
and -9x+ 3y = 3 represent equation 2
The following points are to be noted
- Solving for x or y in equation 1 will definitely lead to having fractions
- Solving for x in equation 2 will also lead to having fractions
Having said that, the step to take to avoid fraction is to solve for y in equation 2
Check

Add 9x to both sides


Divide through by 3


Split fraction


<em>At the point, the expression of y can then be substituted in equation 1</em>
Answer:
y=-x +7 is the slope-intercept form and the graph is shown in the attachment.
Step-by-step explanation:
The given equation is

We solve for y to get:

This is now of the form, y=mx+c
This is called the slope-intercept form.
Since the slope is negative, the graph slopes backwards. Also the y-intercept is 7, so the graph will intersect the y-axis at 7
Answer:
169
Step-by-step explanation:
if S(n)=n^2
so,S(13)=13^2
n=13
n^2=13^2
=169
Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)
Answer:
I thought if you try to do an exponent on a zero, then the answer would always be undefined...
Step-by-step explanation: