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Burka [1]
3 years ago
7

You are planning a trip to the United States. The exchange rate is $1 = 78p Approximately how many dollars will you get if you c

hange £160 for dollars?
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
1 euro = 1.13 dollars
160 euro= 180.30
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Find the x & y-intercepts of the function. f(x)=2(x−1)(x+2)(x−3)
ArbitrLikvidat [17]

Answer:

its in the image below because im too lazy to write it down.

Step-by-step explanation:

8 0
3 years ago
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3. Use the diagram 2 and 3 are ____ angles 1. complementary 2. vertical 3. right 4. supplementary
Vladimir79 [104]

#3

2 and three are supplementary angles .

#4.

The answer is opposite angles .

  • Hence there is no option

#5

Bisected angles are equal

\\ \sf\longmapsto 5x=3x+10

\\ \sf\longmapsto 5x-3x=10

\\ \sf\longmapsto 2x=10

\\ \sf\longmapsto x=\dfrac{10}{2}

\\ \sf\longmapsto x=5

Now

m<ABC

\\ \sf\longmapsto 5x+3x+10

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5 0
2 years ago
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HELP ASAP PLZZ
Nonamiya [84]

Answer:

The Answer is A. 2/5

Step-by-step explanation:

The way i Divide fractions is by if you take the second fraction and swap the numbers around, you can do 7/24 TIMES 48/35. then you multiply the numbers NOT in a crossway like 7 times 35 butin a straight way so its 7 times 48. Doing so will get you 336/840. I simplified this answer by 6 and got 56/140 then i simplified it again by 4 to get 14/35 and once more i simplified it by 7 to get 2/5.

4 0
3 years ago
Angles C and D are supplementary, if angle C equals 126, what is angle D
Elis [28]

Answer:

angle D = 54°

Step-by-step explanation:

Supplementary angles sum to 180°

To calculate D, subtract angle C from 180

angle D = 180° - 126° = 54°


6 0
3 years ago
A card is chosen from a standard deck of cards. What is the probability that the card is a club, given that the card is black?
leonid [27]
From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26 A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace. P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13 WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces? P(AA) = (4/52)(3/51) = 1/221. 1 WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king? P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed. WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the probability of drawing the first queen which is 4/52. The probability of drawing the second queen is also 4/52 and the third is 4/52. We multiply these three individual probabilities together to get P(QQQ) = P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible. Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit) What's the probability of being dealt a royal flush in a five card hand from a standard deck of cards? (Note: A royal flush is a 10, Jack, Queen, King, and Ace of the same suit. A standard deck has 4 suits, each with 13 distinct cards, including these five above.) (NB: The order in which the cards are dealt is unimportant, and you keep each card as it is dealt -- it's not returned to the deck.) The probability of drawing any card which could fit into some royal flush is 5/13. Once that card is taken from the pack, there are 4 possible cards which are useful for making a royal flush with that first card, and there are 51 cards left in the pack. therefore the probability of drawing a useful second card (given that the first one was useful) is 4/51. By similar logic you can calculate the probabilities of drawing useful cards for the other three. The probability of the royal flush is therefore the product of these numbers, or 5/13 * 4/51 * 3/50 * 2/49 * 1/48 = .00000154
5 0
3 years ago
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