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4 years ago

15

Which of the following is the probability that a red or green marble will be selected from a bag containing 9 red marbles 6 blue

marbles 7 green marbles and 11 yellow marbles if one is selected randomly?

1 answer:

Anna11 [10]4 years ago

8 0

P or red or green = 16/ 33

hope it helped

You might be interested in

Give me an explanation please

Nostrana [21]

Answer:

The 3rd and 6th

Step-by-step explanation:

Make a system of equations, try to solve, and then see which statements apply.

let x be the cost of a DVD and y be the cost of a video game

Then you would have:

2x + y = 12

4x + 2y = 24

from turning the words into equations.

Now, solve:

first, multiply the first equation by 2

2x + y = 12 --> 4x + 2y = 24

Then, subtract the two equations:

4x + 2y = 24

- (4x + 2y = 24)

0 = 0

Since you have a number = a number, there are infinite solutions.

Go through the options they give you and see which ones are correct

o The system of linear equations that represents this situation has one solution

Not true, there are infinite

o The system of linear equations that represents the situation has no solution.

Not true

o The system of linear equations that represents the situation has infinitely many solutions.

True

o The DVD rentals cost more than video game rentals

Unknown, it could cost more but it can also cost less so this is not true

o The video rentals cost more than the DVD rentals

Unknown for the same reason

o You cannot determine the cost of video game rentals or DVDs.

True

7 0

3 years ago

A social psychologist wants to know whether students' performance on a problem solving task is lowered by having other people lo

Orlov [11]

Answer:

Yes, there is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.

Step-by-step explanation:

Null hypothesis: The performance on the problem solving task is lowered by having onlookers.

Alternate hypothesis: The performance on the problem solving task is not lowered by having onlookers.

Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)

sample mean = 89.8

population mean = 89.1

sample sd = √sample variance = √84.6 = 9.198

n = 21

Degree of freedom = n-1 = 21-1 = 20

Assuming a 5% significance level

The test is a two-tailed test. Critical values corresponding to 20 degrees of freedom and 5% significance level are -2.086 and 2.086

Test statistic (t) = (89.8 - 89.1) ÷ (9.198/√21) = 0.7 ÷ 2.007 = 0.349

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.349 falls within the region bounded by the critical values.

There is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.

4 0

3 years ago

Find the constant of variation k for the direct variation.<br><br> 2x + 6y = 0

Flauer [41]

Answer:

$k=-\frac{1}{3}$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem we have

$2x+6y=0$

Isolate the variable y

subtract 2x both sides

$2x+6y-2x=0-2x$

$6y=-2x$

Divide by 6 both sides

$y=-\frac{1}{3}x$

therefore

The constant of variation is equal to

$k=-\frac{1}{3}$

5 0

3 years ago

Allie bought 5 pounds of onions at $0.96 per pound, x pounds of squash at

Leno4ka [110]

Dude it’s easy
For onions: 5 x 0.96=4.8
For squash: 0.75x
For corn: 0.84y
Add em up
We get the expression as:
075x+0.84y +4.8
Hope this helps

6 0

3 years ago

AT THANKSGIVING DINNER, EMMA'S FAMILY ATE 1/3 OF A PUMPKIN PIE. WHAT FRACTION OF THE PIE WAS LEFT OVER?

harina [27]

3/3-1/3=2/3 of pie is left over

7 0

3 years ago