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Answer:
1) p1=0.83
2) p2=0.81
3) Option B
4) p=0.82
5) s=0.03
6) z=0.67
7) P=0.50
8) Do not reject H0
Step-by-step explanation:
1) The proportion of Republicans who think the full-body scans should be applied in airports is equal to the ratio between the republicans that think it should over the total Republicans in the poll:
2) The proportion of Democrats who think the full-body scans should be applied in airports is equal to:
3) As we want to know if there is a difference in the proportions calculated, not if one is higher or lower than the other, the correct option is B:
4) The pooled estimate of a proportion is the average of both proportions:
5) The standard error can be calculated as:
6) The z-statistic can be calculated as:
7) The P-value for z=0.67 is P=0.50 (from the standard normal distribution table).
8) If the significance level is 0.01, the P-value is bigger than the significance level. The effect is not significanct. The null hypothesis is not rejected.
There is not enough evidence to say that both proportions are different.
A. Do not reject H0
*Select two choices: one for the centers and one for the spreads.
A. Centers: The sharks have a lower median age than the koi
B. Spreads: The ages of the koi are more spread out.
C. Centers: The sharks have a greater median age than the koi.
D. Spreads: The ages of the sharks are more spread out
(See attachement for diagram)
Answer:
A. and B.
Step-by-step explanation:
Measure of center that can be used in stating the differences between Koi and Shark is the median.
Examining the dot plot, the median age for Sharks is 20.
The median age for Koi is the 14th data point, which is 40.
Thus, for the center, we can conclude that Sharks has a lower median age than Koi.
For the spread, the larger the range, the more spread out the data are.
Thus:
Range for Sharks = 30 - 10 = 20
Range for Koi = 70 - 25 = 45
Therefore, we can conclude that the ages of Koi are more spread out.
