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zimovet [89]
4 years ago
15

If DE = 4x + 10, EF = 2x-1, and DF = 9x-15, find DF

Mathematics
2 answers:
Komok [63]4 years ago
6 0
DE = 4x + 10

EF = 2x -1

DF = DE + EF = 4x + 10 + 2x - 1 = 6x + 9

Given,

DF = 9x - 15

6x + 9 = 9x - 15

3x = 24

x = 8

Hence, DF = 9x - 15 = 9*8 - 15 = 72 - 15 = 57
Dmitrij [34]4 years ago
5 0
Hello,
<span>We have that:
(4x+10)+(2x-1)=9x-15

</span>We solve the equation:
4x+10+2x-1=9x-15;
6x+9=9x-15;
6x-9x=-15-9;
-3x=-24;
3x=24;

<span>from which
</span>x=24:3=8

<span>Then:
DF=9x-15=(9</span>×8)-15=72-15=57

bye :-)
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