PLEASE I NEED HELP URGENT I Will MARKE YOU BRAIN LIST

What is the distance points for (2,-2) and (0,-9)

Ksivusya [100]

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

Step-by-step explanation:

The given is,

Two points are (2,-2) and (0,-9)

Step:1

By graphical method,

For two points (2,-2) and (0,-9)

First point (2,-2)

The values of x=2 and y=-9 noted in the graph

Second point (0,-9)

The values of x=0 and y=-9 noted in the graph

Now join the two points, measure the distance between the two points,

Distance between points are 7.3 units.

( OR )

Step:1

By formula method,

Distance = $\sqrt{(x_{2}- x_{2}) ^{2}+ (y_{2}-y_{1}) ^{2} }$

Where,

( 2,-2) are ( $x_{1},y_{1}$ )

(0,-9) are ( $x_{2},y_{2}$ )

From the values,

= $\sqrt{(0- 2) ^{2}+ (-9+2) ^{2} }$

= $\sqrt{(- 2) ^{2}+ (-7) ^{2} }$

= $\sqrt{4+49 }$

= $\sqrt{53}$

= 7.280

≅ 7.3

Distance = 7.3

Result:

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

5 0

3 years ago

Select the correct answer.

zepelin [54]

Answer:

Answer is option c

Step-by-step explanation:

$given \: equations \: are \\ x - 2y = 15 \: \: and \: 2x + 4y = - 18 \\ divide \: by \: 2 \: in \: second \: equation \\ x + 2y = - 9 \: \: (equation \: 3) \\ adding \: 1and \: 3 \: we \: get \\ 2x = 6 \\ x = 3 \\ substitute \: x = 3 \: in \: equation \: 3 \\ 3 + 2y = - 9 \\ 2y = - 9 - 3 \\ 2y = - 12 \\ y = - 6$

x=3 and y=-6

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

6 0

3 years ago

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What is the Domain and Range of the function f(x)<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx-7%7D%20%2B9" id="TexFormula1" tit

omeli [17]

For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}

<h3>How to get the domain and range?</h3>

Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:

x - 7 ≥ 0.

Solving for x we get:

x ≥ 0 + 7

Then the domain is:

x ≥ 7

To get the range, we evaluate in the minimum of the domain:

f(7) = √(7 - 7) + 9 = 9

Then the range is the set of all values larger than 9, because the function is increasing.

So the range is R: y ≥ 9.

If you want to learn more about domain and range:

brainly.com/question/10197594

#SPJ1

5 0

1 year ago

Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w

Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so $p = 0.6$

The week has 5 days, so $n = 5$

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102$

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768$

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304$

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456$

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so $P(X = 5)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778$

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0

3 years ago

HELPPPPPPPPPP PLEASE

Sophie [7]

Answer:

The answer is in the above attachment.

8 0

2 years ago

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PLEASE I NEED HELP URGENT I Will MARKE YOU BRAIN LIST​

PLEASE I NEED HELP URGENT I Will MARKE YOU BRAIN LIST