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3 years ago

To which of the following sets does the number 0 belong?

Mathematics

2 answers:

LenKa [72]3 years ago

8 0

Answer: integers, rational and whole.

Step-by-step explanation:

1 .The set of Integers is expressed as I={......-3,-2,-1,0,1,2,3,....}

Hence, 0 belongs to set of integers.

2. The set of rationals contains fractions (where denominator ≠ 0) ,terminating and repeating decimals.

Since, 0/1 is also a rational number .

Hence, 0 belongs to set of rationals.

3.The set of whole numbers is expressed as W={0,1,2,3,4,......}

Hence, 0 belongs to set of whole numbers.

4. The set of irrationals contains numbers which cannot be expressed as the ratio of integers, and they are non-repeating, non-terminating decimals.

Hence, 0 does not belongs to irrational.

5. The set of natural numbers is expressed as N={1,2,3,4,5,....}

since it starts from 1.

Hence, 0 does not belongs to set of natural numbers.

posledela3 years ago

7 0

I THINK INTEGERS AND IRRATIONAL BECAUSE INTEGERS ARE ANY NUMBERS AND RATIONAL NUMBERS ARE NUMBERS THAT CAN BE TURNED TO RATIOS SO 0 CANNOT. HOPR THIS HELPED!!!!!!

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Which of the following points is an equal distance (equidistant) from A(0, −4) and B(−2, 0)?

joja [24]

Answer:

Point N(3,0) is equidistant from A and B.

Step-by-step explanation:

In order to check whether the point is equidistant from A and B, it is required to measure the distance of A and B from each point. The formula for distance is:

d= √((x_2-x_(1))^2+(y_2-y_(1))^2 )

For J

AJ= √((-4-0)^2+(-5+4)^2 )

=√((-4)^2+(-1)^2 )

= √(16+1)

= √17 units

BJ=√((-4+2)^2+(-5-0)^2 )

=√((-2)^2+(-5)^2 )

= √(4+25)

= √29 units

Point J is not equidistant from A and B.

For K

AK= √((-3-0)^2+(0+4)^2 )

=√((-3)^2+(4)^2 )

= √(9+16)

= √25 units

BK=√((-3+2)^2+(0-0)^2 )

=√((-1)^2+(0)^2 )

= √(1+0)

= √1

=1 unit

Point K is not equidistant from A and B.

For M

AM= √((0-0)^2+(0+4)^2 )

=√((0)^2+(4)^2 )

= √(0+16)

= √16

=4 units

BM=√((0+2)^2+(0-0)^2 )

=√((2)^2+(0)^2 )

= √(4+0)

= √4

=2 units

Point M is not equidistant from A and B.

For N

AN= √((3-0)^2+(0+4)^2 )

=√((3)^2+(4)^2 )

= √(9+16)

= √25

=5 units

BN=√((3+2)^2+(0-0)^2 )

=√((5)^2+(0)^2 )

= √(25+0)

= √25

=5 units

As point N's distance is equal from A and B, Point N is equidistant from A and B.

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KonstantinChe [14]

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Step-by-step explanation:

Given

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Required

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