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monitta
3 years ago
7

What are the domain and range of f(x) = 2(3X)?

Mathematics
1 answer:
erik [133]3 years ago
5 0
<h3>Answer: Choice A</h3>

Domain: (-\infty,\infty)

Range: (0,\infty)

==============================================================

Explanation:

I'm assuming the function is f(x) = 2(3)^x which is an exponential function.

The domain of any exponential function is the set of real numbers. In interval notation, the domain is (-\infty, \infty) which says we can pick any number between negative infinity and positive infinity: aka any number we want. There are no restrictions to worry about such as division by zero errors.

The range of this exponential function is the set of y values such that y > 0. It often helps to see the graph of what is going on (see below). Note how as x heads to the left, and gets more negative, the curve approaches the x axis. It never actually touches it however. So it will never reach y = 0 itself but instead just get very close. The inequality y > 0 translates to the interval notation (0,\infty)

----------

Summary:

Domain: (-\infty,\infty);  Range: (0,\infty)

So that's why the answer is choice A

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Answer:

a) mean = 0.2

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Step-by-step explanation:

In order to find the mean, variance, and standard deviation, let us for a table for the data:

level            x

1             0.411

2            0.278

3            0.221

4            0.080

5            0.010

Calculating the mean (\bar{x})

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∴Mean = 0.2

level            x         x- \bar{x}         (x - \bar{x})^2  

1             0.411         0.211         0.0445  

2            0.278       0.078        0.0608

3            0.221        0.021         0.000441    

4            0.080        -0.12         0.0144

5            0.010         -0.19         0.0361

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standard deviation = √(variance)

Standard deviation = √(0.0391)

Standard deviation = 0.198

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Step-by-step explanation:

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