55
×35
is 1925. You could use the estimation method if it doesn't require you to use the exact amount.
line segment connecting the vertices of a hyperbola is called the <u>transverse axis</u> and the midpoint of the line segment is the <u>center</u> of the hyperbola.
What is transverse axis and center of hyperbola ?
The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints. The foci lie on the line that contains the transverse axis. The conjugate axis is perpendicular to the transverse axis and has the co-vertices as its endpoints.
And The center of a hyperbola is the midpoint of both the transverse and conjugate axes, where they intersect. Every hyperbola also has two asymptotes that pass through its center. As a hyperbola recedes from the center, its branches approach these asymptotes.
Learn more about the transverse axis and center of hyperbola here:
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The derivative of the function csc (5x) can be determined by following the trigonometric rule of differentiation. In this case, the derivative of csc x is -csc x cot x while that of 5x is 5. The total derivative and the answer to the problem asking for the is <span>derivative of csc(5x) is </span>-5 csc<span> 5x cot 5x. </span>
So this meeting room is 3 by 19 by 12
surface area/wall area=2(height times width)+2(height times depth)+2(width times depth)
lets say 3=height
depth=19
width=12
2(3 times 12)+2(3 times 19)+2(12 times19)=2(36)+2(57)+2(228)=72+114+456=642
2 coats of paint so surface area times 2
642 times 2=1284
assuming 30m means 30 <u>square</u> meters we divide 1284 by 30 and get
1284/30=42 and 4/5 or 42.8
then find how many cans by dividing by 4
42.8/4=10 and 1.4/2=10.7, but you cant buy 0.7 of a can so round up and get
11 cans of paint
he needs 11 cans of paint
Answer:
The answer is given below
Step-by-step explanation:
The question is not complete. The correct question is:
A square based pyramid have a height of 30 cm and base of 10 cm. The The square based pyramid is cut horizontally at a height of 15cm to leave this frustum.
Answer:
The frustum would have a base of 10 cm and height of 15 cm. The lower base has a length of 10 cm. to calculate the upper base, we use the formula:
Substituting:
The volume of the frustum is given by the formula:
Where h is the height of the frustum = 15 cm, A1 is the area of the lower base = 10 * 10 = 100 cm², A1 is the area of the upper base = 5 * 5 = 25 cm²
Substituting gives:
