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3 years ago

Help plz!!!?!?!?!!!!!!!!!!

Mathematics

1 answer:

Lynna [10]3 years ago

4 0

I’m pretty sure the answer would be two 8-6y=2
x -intercept =2

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PLEASE ANSWER ASAP:

user100 [1]

Answer:

The expression: x + 3x + (3x-5)

Step-by-step explanation:

Okay, so x is the amount of $ spent. And three times means 3x, and 5 less on entertainment is 3x - 5. So put the expression together and you get x + 3x + (3x-5). Now plug in 10 for x so 10+3(10) + (3(10) -5).

B. $30

C. $25

D. $65

4 0

3 years ago

What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?

erma4kov [3.2K]

Your function is: $f(x)=\frac{1}{2}\cos \Big( \frac{1}{4x}\Big) -1$

Domain: $(-\infty, +\infty)-\{ 0 \}$ or $R-\{ 0 \}$

Range: $[-\frac{3}{2}, -\frac{1}{2}]$

Midline: $y=-1$

8 0

3 years ago

Read 2 more answers

To make his famous chocolate cake, a baker uses chocolate that is 75% cocoa.

Masja [62]

The baker needs to use 100/3 pounds of 90% chocolate to make the cake.

<h3>Equation </h3>

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the amount of 90% chocolate. Using equation:

100 * 70% + x * 90% = (x + 100) * 75%

100 * 0.7 + 0.9 * x = (x + 100) * 0.75

70 + 0.9x = 0.75x + 75

x = 100/3

The baker needs to use 100/3 pounds of 90% chocolate to make the cake.

Find out more on Equation at: brainly.com/question/22688504

8 0

2 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

3 years ago

Mario and Bowser begin with a hat that has 5 balls in it: 3 are red, 2 are green. Bowser secretly picks a ball and tells Mario i

stiv31 [10]

1) probabillity of getting two red balls in a row is 1/2 (if 80% Bowser is lying)
2) <span>probability of getting 2 red balls in a row is 1/6 (20% Bowser's truth)
3) overall probability </span> $( \frac{4}{5} * \frac{1}{2}) + (\frac{1}{5} * \frac{1}{6}) = \frac{13}{30}$

8 0

3 years ago