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vfiekz [6]
3 years ago
14

Help plz!!!?!?!?!!!!!!!!!!

Mathematics
1 answer:
Lynna [10]3 years ago
4 0
I’m pretty sure the answer would be two 8-6y=2
x -intercept =2
You might be interested in
G = 15 - m/32
IRINA_888 [86]

The value of 32 in the equation will serve as the time taken by the driver to travel

<h3>Functions and values</h3>

If Alice fills up the gas tank of her car before going for a long drive, and the equation that shows the amount of gas in gallons in Alice's car when she has driven m (miles). is given as:

g = 15 - m/32

The value of 32 in the equation will serve as the time taken by the driver to travel

Learn more on distance and time here; brainly.com/question/17273444

#SPJ1

6 0
2 years ago
bonnie runs 1 2/3 times as far as john each day if bonnie runs 5 miles on monday 3 1/2 miles on tuesday and 5 3/4 miles on wedne
nignag [31]

Answer:

3 miles on Monday

2¹/₁₀ miles on Tuesday

3⁹/₂₀ miles on Wednesday

Step-by-step explanation:

We are told that Bonnie runs 1⅔ (⁵/₃) times as far as John each day

This means that John runs ³/₅ times as far as Bonnie.

MONDAY:

Bonnie runs 5 miles on Monday, therefore, John runs:

³/₅ * 5 = 3 miles

TUESDAY:

Bonnie runs 3½ (⁷/₂) miles on Tuesday, therefore, John runs:

³/₅ * ⁷/₂ = ²¹/₁₀ = 2¹/₁₀ miles

WEDNESDAY:

Bonnie runs 5³/₄ (²³/₄) miles on Wednesday, therefore, John runs:

³/₅ * ²³/₄ = ⁶⁹/₂₀ = 3⁹/₂₀ miles

6 0
3 years ago
She uses a scale of 1 centimeter to 6 inches<br> the scale drawing of the front face is
Anastasy [175]

Answer:

change inches into centimeter and then divide it

hope this help

4 0
3 years ago
Use the square root property to solve x^2-9=0<br> Please help and please show work if you can
charle [14.2K]

Answer:

x = 3 or -3

Step-by-step explanation:

So you have the equation x² - 9 = 0

Move the 9 to the other side: x² = 9

Then take the square root of both sides: \sqrt{x^{2} } = ±\sqrt{9}

x = ±\sqrt{9} = ±3

x = 3 or -3

6 0
3 years ago
Read 2 more answers
A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random
Zielflug [23.3K]

Answer: The 95% confidence interval for the mean of x is (94.08, 101.92) .

Step-by-step explanation:

We are given that ,

A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.

i.e. \sigma= 12

Also, it is given that , Sample mean \overline{x}=98 having sample size : n= 36

For 95% confidence ,

Significance level : \alpha=1-0.95=0.05

By using the z-value table , the two-tailed critical value for 95% Confidence interval :

z_{\alpha/2}=z_{0.025}=1.96

We know that the confidence interval for unknown population mean(\mu) is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = Sample mean

\sigma = Population standard deviation

z_{\alpha/2} = Critical z-value.

Substitute all the given values, then the required confidence interval will be :

98\pm (1.96)\dfrac{12}{\sqrt{36}}

=98\pm (1.96)\dfrac{12}{6}

=98\pm (1.96)(2)

=98\pm 3.92=(98-3.92,\ 98+3.92)\\\\=( 94.08,\ 101.92)

Therefore, the 95% confidence interval for the mean of x is (94.08, 101.92) .

6 0
3 years ago
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