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hodyreva [135]
3 years ago
9

The number of pieces of popcorn in a large movie theater popcorn bucket is normally distributed, with a mean of 1610 and a stand

ard deviation of 10. Approximately what percentage of buckets contain between 1600 and 1620 pieces of popcorn?
A. approximately 68%
B. approximately 75%
C. approximately 95%
D. approximately 99.7%

Mathematics
2 answers:
Elena L [17]3 years ago
7 0

Answer:

A. Approximately 68%

Step-by-step explanation:

Number of pieces of popcorn in a bucket is normally distributed.

Mean = μ = 1610

Standard deviation = б = 10

We know that in normal distribution, approximately 34% of bags will fall with in one standard deviation on one side. On both sides within the range of 1 standard deviation, 34 + 34 = 68 % of bags will fall.

A table of normal distribution about mean is attached for better understanding.

Our range is:

1600 to 1620

1610 - 10 to 1610 + 10

μ ± б

mean ± 1 standard deviation

Our range is within 1 standard deviation. Hence, Approximately 68% of buckets contain between 1600 and 1620 pieces of popcorn.

bearhunter [10]3 years ago
6 0

Answer:

a

Step-by-step explanation:

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