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2 years ago

Elena has some bottles of water that each hold 17 fluid ounces.

Mathematics

1 answer:

Svet_ta [14]2 years ago

6 0

Answer:

17b = w

Step-by-step explanation:

17 times the number of bottles = the number of ounces of water

Then you just plug in the numbers you are given

17(51) = w

17 x 51 = 867

51 bottles of water holds 867 ounces

17b = (51)

divide both sides by 17

51/17 = 3

b = 3

It would take 3 bottles of water to hold 51 ounces

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PLEASE HELP ASAP (timed) Twice the sum of the square of 12 and five

Dmitry [639]

(12^2 + 5) x 2

There you go. I wasn't sure if I was supposed to write an equation or...

= 298

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2 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago

Data collected from a coffee shop indicate that the price

kozerog [31]

The answer is 1/2 I think or 1

7 0

2 years ago

Read 2 more answers

PLEASE HELP IMMEDIATELY

grandymaker [24]

Answer:

a) C(d) = 37.95 + 0.62d

b) C(74) = 37.95 + 0.62(74)

83.8 dollars

c) 8181 miles

Step-by-step explanation:

The company charges a fee of 37.95 just for the rent and then 0.62 dollars per mile.

So if one person travels one mile they will pay:

37.95 + 0.62

Two miles: 37.95 + 0.62 (2)

Three miles: 37.95 + 0.62 (3)

d miles: 37.95 + 0.62(d)

Thus, the function C(d) that gives the total cost of renting the truck for one day if you drive d miles would be C(d) = 37.95 + 0.62d

Now, if we drive 74 miles, the function that gives us the cost would be:

C(74) = 37.95 + 0.62(74) = 37.95 + 45.88 = 83.83 = 83.8 dollars

Now, if we have 5110 dollars on our budget, we would have to substitute this in our function to know how many miles we can drive with that amount:

$C(d)= 37.95+0.62d=5110\\37.95+0.62d=5110\\0.62d=5110-37.95\\0.62d=5072.05\\d=5072.05/ 0.62 \\d=8180.7$

Thus, we could drive 8181 miles

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3 years ago

Could ΔABC be congruent to ΔADC by SSS? Explain. Yes, but only if AB ≅ DC. Yes, but only if BC ≅ DC. No, because AB is not congr

Sonbull [250]

Answer:

Yes, but only if BC ≅ DC; Option B

Step-by-step explanation:

There are 4 possible ways to determine whether two triangles are congruent, and they are the following ;

ASA ( Angle - Side - Angle ),

SAS ( Side - Angle - Side ),

AAS ( Angle - Angle - Side ), and

SSS ( Side - Side - Side )

It is known here that we must prove these triangles congruence through SSS. A triangle can thus be made possible through the congruence of corresponding sides;

Now if we were to create these triangles it would be that BC and DC are, if the triangles were to coincide with one another, the apparent same length if it were that these two Δs really are ≅. Thus;

Solution; Yes, but only if BC ≅ DC

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3 years ago