Tabitha Tidbits costs $7 per bag, and Figaro Flakes is $5.50 per bag.
You need to set up a system of equations. Use "x" for Tabitha Tidbits and "y" for Figaro Flakes, and let the total cost of each trip equal c. Using the equation ax+by=c, substitute the cost of each trip in for c, and the number of bags for each food for a and b respectively. The two equations will be:
3x+4y=43
3x+6y=54
Isolate x in the first equation and you will get:
x=(43-4y)/3
Substitute the above equation for x into the other equation:
3*((43-4y)/3)+6y=54
Isolate y in this equation, and you will get 11/2, which is 5.5
So the cost of one bag of Figaro Flakes is $5.50
Now substitute this into the equation where you isolated x:
(43-4(5.5))/3
You will get x=7, so a bag of Tabitha Tidbits is $7
Answer:
(-1,1)
Step-by-step explanation:
Producing 73.8 units gives the lowest possible average cost.
The average cost (AC) is the ratio of the total cost to the number of units produced. It is given by:
AC = C(x) / x
AC = (0.2x³ – 24x² + 1514x +30064) / x
AC = 0.2x² - 24x + 1514 + 30064/x
The lowest possible average cost is at AC' = 0. Hence differentiating the average cost, gives:
AC' = 0.4x - 24 - 30064/x²
0.4x - 24 - 30064/x² = 0
0.4x³ - 24x² - 30064 = 0
Solving the cubic polynomial gives:
x = 73.8 units
Therefore the lowest possible average cost is when 73.8 units are produced.
Find out more at: brainly.com/question/20346871
Distribute
4x(2x^2-4x+5)-5x(2x+6)
8x^3-16x^2+20x-10x^3-30x
Combine Like Terms
8x^3-16x^2+20x-10x^3-30x
-2x^3-16^2+20x-30x
Combine like terms
-2x^3-16x^2 +20x-30x
-2x^3-16x^2-10x
Common factor
Factor by grouping
-2x^3 - 16x^2-10x
Find one factor
-2(x^3+8x^2+5x)
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<h2>Your answer: -2x(5x^2+4x+5)</h2><h2>(Simplified = 10x^3 + 8x^2 + 10x)</h2>
