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slava [35]
4 years ago
15

A band earns $400.00 for playing at a festival. Their manager is paid 10% of the money earned and the band is saving 15% of the

money earned to put towards recording expenses. How much money is left for the band to split? $
Mathematics
2 answers:
Evgesh-ka [11]4 years ago
7 0

Answer:

300.00

Step-by-step explanation:

ASHA 777 [7]4 years ago
6 0
$300.00 is left for the band to split.
$400.00 - 25% = $300.00

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(2a^2b + 3ab^2 - b^3) - (4b^3 - 3ab^2 -6a^2b)
skelet666 [1.2K]

<em>Hi there!</em>

<em>~</em>

<em></em>(2a^2b+3ab^2-b^3)-(4b^3-3ab^2-6a^2b)<em></em>

<em>Distribute the Negative Sign:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -1(4b^3 - 3ab^2 - 6a^2b)\\= 2a^2 b + 3ab^2 + - b^3 + -1 (4b^3) + -1 (-3ab^2) + -1 (-6a^2b)\\= 2a^2 b + 3ab^2 + -b^3 + -4b^3 + 3ab^2 + 6a^2 b<em></em>

<em>Combine Like Terms:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -4ab^3 + 3ab^2 + 6a^2 b\\= (2a^2 b + 6a^2 b) + ( 3ab^2 + 3ab^2) + (-b^3 + -4b^3) \\= 8a^2 b + 6ab^2 + -5b^3<em></em>

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<em>Hope this helped you!</em>

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3 years ago
A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day
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Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

A(t) = A(0)e^{-kt}

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

A(t) = A(0)e^{-0.1392t}

Find the substance's half life, in days.

This is t for which A(t) = 0.5A(0). So

A(t) = A(0)e^{-0.1392t}

0.5A(0) = A(0)e^{-0.1392t}

e^{-0.1392t} = 0.5

\ln{e^{-0.1392t}} = \ln{0.5}

-0.1392t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.1392}

t = 4.98

The substance half-life is of 4.98 days.

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