2:16+5:54= 8:10 I think this is the answer
5 hours and 54 minutes
Answer:
(11/15)'s
Step-by-step explanation:
(2/5) is equal to (6/15)
(1/3) is equal to (5/15)
(5/15)+(6/15)=(11/15)
<span>The average length of crocodiles in a swamp is 11.5 feet. if the lengths are normally distributed with a standard deviation of 1.7 feet, find the probability that a crocodile is more than 11 feet long.
solution:
To obtain P(x>11) we first need to obtain the value of the z-score:
z=(11-11.5)/1.7
thus
z=-0.2941
thus
P(x>11)=1-P(z<-0.2941)=1-0.3859=0.6141
</span>
you have a 1/6 probability of rolling a 6
so for 3 6's it would be
1/6 x 1/6 x 1/6 = 1/216
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
