2 years ago

Susan incorrectly factored the expression below.

Mathematics

1 answer:

Vlad [161]2 years ago

7 0

12a+15b+9 cause 3*4a=12a 3*5b=15 and 3*3=9

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Step-by-step explanation:

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3 years ago

In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of one half, wha

uysha [10]

The angle of sine has a value of 3/5.

Option A is the correct representation of angle sin(b°).

<h2>How do you calculate the angle b for sine?</h2>

Given that tan(b°) = 3/4 and cos(b°) = 4/5.

In trigonometry, we know that,

$\dfrac {sin \theta}{cos \theta} = tan \theta$

The angle of sine can be written as below.

$sin \theta = cos \theta \times tan \theta$

For the angle b, the above expression can be written as,

$sin (b^\circ) = cos (b^\circ) \times tan (b^\circ)$

Substituting the values in the above expression, we get,

$sin (b^\circ) = \dfrac {3}{4} \times \dfrac {4}{5}$

$sin (b^\circ) = \dfrac {3}{5}$

Hence we can conclude that the angle of sine has a value of 3/5.

To know more about the angle of sine, follow the link given below.

brainly.com/question/2512010.

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2 years ago