Let the number of nickels be = x
Let the number of dimes be = d
Let the number of quarter be = n
Given is, she has twice as many dimes as quarters
d=2n or n = 0.5d
She has two less quarters than nickles.
n= x-2 or
x= n+2
Total values of coins is = $2.60

Now replace x with (n+2) and d with 2n





Now x=n+2 ; x=5+2 = 7
d=2n ; d=2(5) = 10
Hence, Elina has 7 nickels, 10 dimes and 5 quarters.
Answer:
76.0
Step-by-step explanation:
Answer: 140
Step-by-step explanation:
Given t = 5 snd q = 4, tq = 5x4= 20
7tq will be: multiply the value of tq by 7
=7× 5×4
7 × 20 = 140
I hope this is clear.
Answer:
Step-by-step explanation:
Comment
If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)
Givens
Arc EG = 127
Arc DF = 49
Solution
<DCF = 1/2(127 - 49)
<DCF = 1/2(78)
<DCF = 39
Answer:
Mean = 33+ 22+35+27+23+35+27+36 = 238/8 = 29.75
Median = 27+23 = 50/2 = 25
Mode = 35
Range = 36 - 22 = 14
Step-by-step explanation:
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