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Feliz [49]
3 years ago
6

Find the x value to 3x+9=6 and 3x+9=-6

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer:

faffafafs

Step-by-step explanation:

fafasfasfafafafa

Gennadij [26K]3 years ago
3 0

Answer:

for the first one its x=5

for the second x=−5

one its Step-by-step explanation:

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Please help!!!!!!!!!
Musya8 [376]

Answer:

what the what lolllll

Step-by-step explanation:

7 0
3 years ago
Mindy makes an annual salary of $24,590. What is the maximum monthly rent she could afford to pay?
Otrada [13]
24590/12=2029.166....
Your answer would be $2049.17
6 0
3 years ago
Read 2 more answers
The circumference of a circle of diameter 3,5 cm is 11 cm. What is the circumference of a circle of diameter 42 cm? Answer ... c
andreyandreev [35.5K]

Answer:

131.95 cm

Step-by-step explanation:

The Formula for the circumference of a circle is πd where d is the diameter. Therefore you simply multiply 42 with PI to get the circumference

5 0
3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
4 years ago
A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:
Kaylis [27]

Answer:

A.

mean = 724.2

Median = 715

Mode = 768

B.

Range = 85

Standard deviation = 29.30

C.

Interval = [665.6, 782.8]

Step-by-step explanation:

Number of samples n = 25

Summation X= 769 + 691 + 699 +730+711+ 765+ 702 718 +719 +712+ 768 +688 +757+695 768 +735 +709 +758 +708+ 693 +736 700+ 687 +772 +715 = 18105

A.

1. Mean = 18105/25

= 724.2

2. Median is the middle value when arranged from the least value to the highest = 715

3. Mode is the number with the highest frequency = 768 (occured two times)

B.

1. Range = highest value - lowest value

Highest value = 772

Lowest value = 687

772-687 = 85

2. Standard deviation = √(X-barX)²/n-1

= √20604/25-1

=√858.5

= 29.30

Please check attachment for the full calculation of the standard deviation

C.

Interval

[Mean - 2(sd), mean + 2(sd)]

= [724.2-2x29.3, 724.2+2x29.3]

=[665.6, 782.8]

4 0
3 years ago
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