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lyudmila [28]
4 years ago
8

Write a multiplication problem using two decimals that has a product greater than 0.1 but less than 0.2

Mathematics
1 answer:
Umnica [9.8K]4 years ago
5 0
0.9×0.2=0.18
that is one
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Sue has $2.20 in dimes and nickels. If she has 13 more dimes than nickels, how many of each coin does she have?
dem82 [27]
10d+5n=220
divide both sides by 5
2d+n=44

d=13+n
sub 13+n for d in other equatin

2(13+n)+n=44
26+2n+n=44
26+3n=44
minus 26 both sides
3n=18
divide both sides by 3
n=6
sub back

d=13+n
d=13+6
d=19


19 dimes
6 nickles
4 0
3 years ago
SUPER DUPER EASY but need help!
Mandarinka [93]

Answer:

D.) 1 + 1 + 5/8 + 2/8

Step-by-step explanation:

1 5/8 + 1 1/4

*set aside ones for a sec*

1/4 x 2/2 = 2/8

5/8 + 2/8

*get the ones back in*

1 + 1 + 5/8 + 2/8

5 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
lions [1.4K]
10, 10, 20 or either of u talking abt about tah the whole either 0-100
7 0
3 years ago
What is the product of three square root of eight times four square root of three? Simplify your answer.
igor_vitrenko [27]
The\ product\ of 3 \sqrt{8}*4 \sqrt{3}\ is\ 24 \sqrt{6}.


First, recognize that all the numbers can be moved around because they are being multiplied together.
Next, rearrange the expression so that the whole-number coefficients are together:

3\sqrt{8}*4\sqrt{6}
3*4*\sqrt{8}*\sqrt{3}

Now try to simplify the square-roots to find any squares inside that can be reduced and taken out of the square-root:

3*4*\sqrt{(2*2*2)}*\sqrt{3}
3*4*\sqrt{4*2}*\sqrt{3}

Multiply the square roots together:
3*4*\sqrt{(4*2*3)}
3*4*\sqrt{(4*6)}

Now take out the square-root of 4 and simplify
3*4*\sqrt{4}*\sqrt{6}
3*4*(2)*\sqrt{6}
24\sqrt{6}

Thus,\ your\ answer\ is\ 24\sqrt{6}
7 0
3 years ago
HELP QUICKLY PLSSS!!!!!!!!!!<br><br> Evaluate square root -75s where s = -3
lord [1]

Answer:

15

Step-by-step explanation:

-75 x-3 is 225

Square root of 225 is 15

3 0
3 years ago
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