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astraxan [27]
3 years ago
15

3(x+1)^(4/3)=48 how do i solve this?

Mathematics
1 answer:
IrinaK [193]3 years ago
4 0
3(x+1)^{\frac{4}{3}}=48\\\\\frac{3(x+1)^{\frac{4}{3}}}{3}=\frac{48}{3}\\\\(x+1)^{\frac{4}{3}}=(x+1)^{(\frac{1}{3}*4)}=\sqrt[3]{(x+1)^{4}}=16\\\\(\sqrt[3]{(x+1)^{4}})^{3}=16^{3}\\\\(x+1)^4=4096\\\\\sqrt[4]{(x+1)^4}=\sqrt[4]{4096}=\pm8\\\\\\x+1=\pm8\\\\x+1=8\\x=7\\\\x+1=-8\\x=-9

Your answers are x = 7 and x = -9.
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svetoff [14.1K]

Answer:

1) 396

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Step-by-step explanation:

* Lets explain how to solve the product mentally

# Remember the distributive property can help you to find the product

  mentally the distributive property ⇒ a(b + c) = ab + ac

- Lets solve them

1)

- In 9 × 44 we can write 44 as (40 + 4)

∴ 9 × 44 = 9(40 + 4)

∵ 9(40 + 4) = 9 × 40 + 9 × 4

- Now lets multiply 9 by 40 and 9 by 4

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∴ 9 × 40 + 9 × 4 = 360 + 36 = 396

∴ 9 × 44 = 396

2)

- In 4 × 5 1/8 we can write 5 1/8 as (5 + 1/8)

∴ 4 × 5 1/8 = 4(5 + 1/8)

∵ 4(5 + 1/8) = 4 × 5 + 4 × 1/8

- Now lets multiply 4 by 5 and 4 by 1/8

∵ 4(5) = 20

∵ 4(1/8) = 1/2

∴ 4 × 5 + 4 × 1/8 = 20 + 1/2 = 20 1/2

∴ 4 × 5 1/8 = 20 1/2

3)

- In 7 × 3.8 we can write 3.8 as (3 + 0.8)

∴ 7 × 3.8 = 7(3 + 0.8)

∵ 7(3 + 0.8) = 7 × 3 + 7 × 0.8

- Now lets multiply 7 by 3 and 7 by 0.8

∵ 7(3) = 21

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∴ 7 × 3 + 7 × 0.8 = 21 + 5.6 = 26.6

∴ 7 × 3.8 = 26.6

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4)

- In 8(x + 7) we will multiply 8 by x and 8 by 7 and add them

∵ 8 × x = 8x

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∴ 8(x + 7) = 8x + 56

5)

- In 6(11 + x) we will multiply 6 by 11 and 6 by x and add them

∵ 6 × 11 = 66

∵ 6 × x = 6x

∴ 6(11 + x) = 66 + 6x

6)

- In 8(x + 1) we will multiply 8 by x and 8 by 1 and add them

∵ 8 × x = 8x

∵ 8 × 1 = 8

∴ 8(x + 1) = 8x + 8

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Answer:

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