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3 years ago

3(x+1)^(4/3)=48 how do i solve this?

1 answer:

4 0

$3(x+1)^{\frac{4}{3}}=48\\\\\frac{3(x+1)^{\frac{4}{3}}}{3}=\frac{48}{3}\\\\(x+1)^{\frac{4}{3}}=(x+1)^{(\frac{1}{3}*4)}=\sqrt[3]{(x+1)^{4}}=16\\\\(\sqrt[3]{(x+1)^{4}})^{3}=16^{3}\\\\(x+1)^4=4096\\\\\sqrt[4]{(x+1)^4}=\sqrt[4]{4096}=\pm8\\\\\\x+1=\pm8\\\\x+1=8\\x=7\\\\x+1=-8\\x=-9$

Your answers are x = 7 and x = -9.

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A 5/16 inch bolt weighs 0.43 lb. How many bolts are there in a 125 lb. keg?

Gemiola [76]

Answer:

290 Bolts are There

Step-by-step explanation:

5/16 bolt Here 5/16 is size of Bolt

1 bolt Weighs of given size weighs = 0.43 lb

Total Weight = 125 lb

Number of Bolts in Bag = Total Weight of Bag / Weight of 1 Bolt

= 125/0.43

= 290

4 0

3 years ago

the height in feet h of a model rocket t seconds after launch is given by the equation h(t)=3+70f-16t^2

olga55 [171]

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7 0

4 years ago

Answers for the 2 boxes please

Andreas93 [3]

Answer:

(5,14)

Step-by-step explanation:

4x+6=2x-4

2x=10

x=5

y=2x+4

y=2(5)+4

y=14

4 0

3 years ago

The temperature of magnesium must be at least 650 degrees for the metal to melt. A sample of magnesium is currently 255 degrees.

Agata [3.3K]

The total temperature of the magnesium sample is its original temperature plus the temperature increase which is dependent on time. This total should exceed 650 degrees. Thus, the inequality that best describes the condition is,
255 + 10m ≥ 650
m ≥ 39.5
The answer is letter b.

8 0

4 years ago

Examine the required sample size needed to be able to

Xelga [282]

Answer:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=500$ represent the population standard deviation assumed

n represent the sample size (variable of interest)

Confidence =98% or 0.98

ME = 10 represent the margin of error desired

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.01;0;1)", and we got $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

So the answer for this case would be n=13573 rounded up to the nearest integer

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

3 0

4 years ago