Answer:
The required equation is
4p = 2.24
And p = 0.56 [ where p is in $]
Step-by-step explanation:
Given that Selena buys 4 peaches that weight 1 pound in all.
Peaches are on sale for $2.24 per pound.
Since the total weight of peaches is 1 pound.
So the price of 4 peaches is $2.24.
Let p be the price of 1 peaches.
Then the price of 4 peaches is $(4×p)
= $4p
According to the problem,
4p = 2.24

⇒p=0.56 [ where p is in $]
The required equation is
4p = 2.24
And p = 0.56 [ where p is in $]
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Given:
W(width) = (6L) - 9
L(length) = L
Equation:
2( [ 6L ] - 9) + 2 (L) = 150
= 12L - 18 + 2L = 150
= 12L + 2L = 150 + 18
=14L = 168
L = 168/14, so the length is 12. Let's check our work.
Width: 6(12) - 9 = 72 - 9 = 63
Length: 12
Since there are two lines of width and two lines of length:
2(12) + 2(63) = 24 + 126, which gives you a perimeter of 150 mm.
Hope this helped.
I think the best answer is 3 to 9 but thats not a answer so 3 to 6