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3 years ago

14

Leah is saving money to buy her sister a graduation gift. She needs $44 and she has saved 25%of this amount so far. How much mor

e money must Leah saved

1 answer:

ehidna [41]3 years ago

3 0

Leah must save $33 more dollars.

$44 x 25% = $11
$44 - $11 = $33

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The triangle is obtuse and scalene.

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3 years ago

What is the linear equation for this table?

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Answer:

y=-2x-5

Step-by-step explanation:

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(08.06)The following data show the weight, in ounces, of 10 different bags of candy: 10 3 7 3 4 21 6 10 1 2 4 After removing the

hoa [83]

Answer:

B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):

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We now divide this by the number of data points:

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This is a measure of how much each bag of candy varies from the mean.

4 0

3 years ago

Read 2 more answers

You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the

Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a) How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

substituting the values

$A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}$

$A=300\cdot \frac{2.06}{2}$

$A=\frac{618}{2}$

$A=309$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

so substituting the values

$A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}$

$A=300\cdot \frac{2.06^2}{2^2}$

$A=318.27$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.

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3 years ago

Find the area of the shape shown below.

sveticcg [70]

Answer:

A = 15u²

Step-by-step explanation:

Area of a Trapezoid Formula:

$\frac{h}{2}*(b_1+b_2)$

Plug in our values (h = 3, b1 = 7, b2 = 3)

$\frac{3}{2}*(7+3)$

Now we evaluate

$\frac{3}{2}*(10)$

$\frac{30}{2} = 15$

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2 years ago