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kogti [31]
3 years ago
12

What is the “mean” of this number sequence? 4, 2, 2, 2, 5, 15

Mathematics
2 answers:
mamaluj [8]3 years ago
6 0
The answer is 5. 
You add all the numbers together then divide by the amount of number there are.
4+2+2+2+5+15=30 
30/6=5
Debora [2.8K]3 years ago
4 0
The mean is found by dividing the sum of all terms by the number of terms present in the set.

Set up the equation:

\frac{2 + 2 + 2 + 4 +5 + 15}{6} = \frac{30}{6} = 5

The mean of this sequence is 5.

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What is the standard form of 65
otez555 [7]
The standard form would be 65 right?
3 0
3 years ago
4. The perimeter of a triangle is 105 inches. The longest side is 22 inches longer than the shortest side. The sum of the
Cloud [144]

Answer:

x = 45

y = 37

z = 23

Step-by-step explanation:

x + y + z = 105

x = z + 22

x + 15 = y + z

(z + 22) + 15 = y + z

              37 = y

           x + y + z = 105

(z + 22) + 37 + z = 105

                     2z = 46

                       z = 23

    x + y + z = 105

x + 37 + 23 = 105

               x = 45

3 0
2 years ago
The distance between the jones house and the smith house is 96 feet.How many yards is that?
Sindrei [870]
3 ft = 1 yd
96/3 = 32
Answer: 32 yds
5 0
3 years ago
An Olympic swimming pool is 50 m long, 25 m wide, and 1.5 m deep. How many Olympic pools would be filled by the dollar bills spe
Gelneren [198K]

Answer:

Number of dollars bills that can be fitted in Olympic pool = 1.67 billion.

Step-by-step explanation:

The dimensions of a dollar bill are 15.5956 cm by 6.6294 cm by 0.010922 cm. The U.S. federal government spent $3.8 trillion in fiscal year 2011.

An Olympic swimming pool is 50 m long, 25 m wide, and 1.5 m deep. How many Olympic pools would be filled by the dollar bills spent by the U.S. federal government in 2011

From above,

The volume for the dimension of the dollar bill = 15.5956 cm × 6.6294 cm × 0.010922 cm

The volume for the dimension of the dollar bill = 1.12922 cm³

The volume for the dimension of the dollar bill = 1.12922 × 10⁻⁶ m³

The volume of the pool = 50 m  ×  25 m  ×  1.5 m

The volume of the pool = 1875 m³

Number of dollars bills that can be fitted in pool = volume of the pool/volume of the dimension of dollar bills

Number of dollars bills that can be fitted in Olympic pool =1875 m³ / 1.12922 × 10⁻⁶ m³

Number of dollars bills that can be fitted in Olympic pool = 1,660,438,180

Number of dollars bills that can be fitted in Olympic pool = 1.67 billion.

8 0
3 years ago
What percent of 25 is 20
ipn [44]
80% bc 20/25 equals 4/5 and 4/5 equals x/100 and when you do that math it equals 80%
7 0
3 years ago
Read 2 more answers
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