Answer:
![\frac{10}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B9%7D)
Step-by-step explanation:
1 .1 ( .1 repeating) = ![\frac{10}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B9%7D)
Let x=0.1
Then 10x = 1.1111...
= 10 + 0.(1)
= 10+ x.
So, 9x=10 and lastly, x= ![\frac{10}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B9%7D)
1.
Seven hundred twenty-five
2.
Two hundred thirteen
Answer: i think its implied
Step-by-step explanation:
Answer:
Ф = ![\frac{\pi }{4} ,\frac{5\pi}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%2C%5Cfrac%7B5%5Cpi%7D%7B4%7D)
Step-by-step explanation:
It is a bit difficult to input the work here, so I uploaded an image
- First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
- Then we can combine like terms
- Then we can factor this as a polynomial function
- Then we can set each term equal to zero and solve for Ф
- The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
- The second term tan(Ф) - 1 = 0 has two solutions of
and
so these are the solutions to the problem
Answer:
200,000
Step-by-step explanation:
I think this is the answer