Question

Sixty nine percent of U.S households play video or computer games. Chose 4 heads of households at random. Find the probability that none play video/computer games?

Answer 1

Answer: 1*(69/100)^0*(31/100)^4 = 0.0092 or 0.0092*100 = 0.92%

Answer 2

Answer: 0.00923521

Step-by-step explanation:

Given : The probability U.S households play video or computer games=69%=0.69

here, the probability of each U.S household play video or computer games is fixed as 0.69

Then, the probability of each U.S household not play video or computer games= 1-0.69=0.31

For independent events the probability of their intersection is product of probability of each event.

Now, the probability that none play video/computer games will be :-

$(0.31)^4=0.00923521$