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4 years ago

PLEASE HELP!!!

2 answers:

4 0

(1+tan²x)/(tan²x) =

1/tan²x + tan²x/tan²x =

cos²x/sin²x + 1 =

cos²x/sin²x + sin²x/sin²x =

(cos²x + sin²x) / sin²x =

1/sin²x =

csc²x.

QED

Aloiza [94]4 years ago

4 0

Answer:

sin^2(x)-sin(x)=0

Step-by-step explanation:

(1+tan^2(x))/(tan^2(x)) = csc^2(x)

(I don't want to type out how every step looks because it would take a year but i listed every step I used)

Determine the defined range

Transform the expressions

Apply the exponents

Write all numerators above the common denominator

Simplify the expressions

1/(sin^2(x))=1(sin(x))

set the denominators equal

sin^2(x)=sin(x)

move epression to the left

sin^2(x)-sin(x)=0

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