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3 years ago

What is the approximate volume of a tree trunk if the trunk is 13 feet tall with a circumference of 4.5 feet?

2 answers:

Klio2033 [76]3 years ago

6 0

((I've used 3.14 as pi))

Diameter = circumference / pi
= 4.5 / 3.14
= 1.43

Radius = diameter / 2
= 1.43 / 2
= 0.72

V = pi * r^2 * h
= 3.14 * 0.72^2 * 13
= 21.17
= B

Murrr4er [49]3 years ago

4 0

I believe it's 9.4 feet, in my result

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If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

$csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}$

Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

8 0

2 years ago

Ariana's grandfather made a scaled down model of a knitting needle to be placed inside a dollhouse. Arianna measured the model b

Andrew [12]

Answer:

10.5

Step-by-step explanation:

1.5 inches

.5 and 1.5 =3

3x3.5=10.5

3 0

2 years ago

Read 2 more answers

How do you do this problem??

ELEN [110]

It is a.
You multiply 9.3 and 2.5 together and get 23.25
Then just add the exponents 6+3 is 9
So the answer is 23.25 x 10^9
Hope this helps!!

7 0

2 years ago

Use the commutative law of addition to write a equivalent expression ab+c

Scilla [17]

Answer:

c + ab

Step-by-step explanation:

The way an expression is written is the given you have presented to us.

The commutative law of addition would turn it around as

c + ab.

It just means change the order when adding. Not all systems allow this. It matters which way you put it in some systems.

5 0

3 years ago

The county hospital is located at the center of a square whose sides are 3 miles wide. If an accident occurs within this square,

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

The x-coordinate of the accident is a random variable of uniform distribution with range [-1.5,1.5]. The same can be said for the y-coordinate. However, |x| and |y| are also uniform variables with range [0,1.5], since we still have the same probability on every pair of intervals with the same lenght.

Note that |X| and |Y| are independent with each other, therefore E(|x|+|y|) = E(|x|) + E(|y|) = 2*E(|x|). The last equality holds because both x and y are identically distributed, then so are |x| and |y|.

E(|x|) = $\int\limits^{1.5}_0 {\frac{x}{1.5} \, dx = \frac{2}{3}* ((1.5^2)/2 - 0^2/2) = \frac{3}{2}$

Therefore, E(|x| + |y|) = 2 * 3/2 = 3.

I hope that works for you!

4 0

3 years ago