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Whitepunk [10]
3 years ago
12

What is the approximate volume of a tree trunk if the trunk is 13 feet tall with a circumference of 4.5 feet?

Mathematics
2 answers:
Klio2033 [76]3 years ago
6 0
((I've used 3.14 as pi))

Diameter = circumference / pi
= 4.5 / 3.14
= 1.43

Radius = diameter / 2
= 1.43 / 2
= 0.72

V = pi * r^2 * h
= 3.14 * 0.72^2 * 13
= 21.17
= B
Murrr4er [49]3 years ago
4 0
I believe it's 9.4 feet, in my result
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Leto [7]

Answer:

i think it is A but im not too sure

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3 years ago
The probability that a person is accepted for admission to a specific university is 0.6. Determine the probability that exactly
frozen [14]

Answer: the probability that exactly two of the next five people who apply to that university get accepted is 0.23

Step-by-step explanation:

We would number of people that applies for admission at the university and gets accepted. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 0.6

q = 1 - p = 1 - 0.6

q = 0.4

n = 5

the probability that exactly two of the next five people who apply to that university get accepted is

P(x = 2) = 5C2 × 0.6^2 × 0.4^(5 - 2)

P(x = 2) = 10 × 0.36 × 0.064

P(x = 2) = 0.23

8 0
3 years ago
Read 2 more answers
What is the sum of the interior angles of a pentagon
Juliette [100K]
3 \pi radians
8 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
What value could be added to 2/15 to make the sum greater than 1/2
Lera25 [3.4K]
1/2 - 2/15= 15-4/30 = 11/30  this means that if you were to add 11/30 to 2/15 is exactly equal to 1/2, to fully answer your question you can use any value above that like 12/30 (keep in mind you have to simplify) = 6/15 = 2/5. But then again your question says to add any number to make it greater than 1/2 so technically you could just add 100 or 200 or 1/2 to make the sum of it greater than one half
7 0
3 years ago
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