∆y is change in y (velocity) and ∆x is change in x (time)
So from the graph we see that ∆y is zero and ∆x is also zero (value is changing with same ratio)
∆y/∆x= slope = 0
Answer:
It keeps particles that make up protons and neutrons together.
Explanation:
Nuclear force is a short range of force which means it will act at short range of distance like fermi order distance.
This shows the order of radius of the nuclei which means all the neutrons and protons which resides into the nucleus will exert the nuclear force on each other and this nuclear force is of large magnitude compare to electrostatic force or gravitation force between them.
While if the distance is more than the fermi order distance then the nuclear force totally disappears so it will not exist for large distances.
so here the correct answer must be
It keeps particles that make up protons and neutrons together.
This is weird.
All three 'choices' are true.
Line um up. (a) shows how to solve the problem. (b) does it. and (c) is the answer.
Answer:
emf = - 0.622 V
Explanation:
The electromotive force is given by Faraday's law
emf =
Ф = B. A
bold indicates vectors
Ф = B A cos θ
in this case it is indicated that the magnetic field is constant and the angle between the magnetic field and the normal to the area is parallel, so the cos 0 = 1
we substitute
emf =
the area of the circle is
A = pi r²
emf = B 2π r
speed is defined
v =
we substitute
emf = - 2π B r v
let's calculate
emf = - 2π 0.5 1.65 π0.12
emf = - 0.622 V
Answer:
2.8 cm
Explanation:
= Separation between two first order diffraction minima = 1.4 cm
D = Distance of screen = 1.2 m
m = Order
Fringe width is given by
![\beta_1=\dfrac{y_1}{2}\\\Rightarrow \beta_1=\dfrac{1.4}{2}\\\Rightarrow \beta_1=0.7\ cm](https://tex.z-dn.net/?f=%5Cbeta_1%3D%5Cdfrac%7By_1%7D%7B2%7D%5C%5C%5CRightarrow%20%5Cbeta_1%3D%5Cdfrac%7B1.4%7D%7B2%7D%5C%5C%5CRightarrow%20%5Cbeta_1%3D0.7%5C%20cm)
Fringe width is also given by
![\beta_1=\dfrac{m_1\lambda D}{d}\\\Rightarrow d=\dfrac{m_1\lambda D}{\beta_1}](https://tex.z-dn.net/?f=%5Cbeta_1%3D%5Cdfrac%7Bm_1%5Clambda%20D%7D%7Bd%7D%5C%5C%5CRightarrow%20d%3D%5Cdfrac%7Bm_1%5Clambda%20D%7D%7B%5Cbeta_1%7D)
For second order
![\beta_2=\dfrac{m_2\lambda D}{d}\\\Rightarrow \beta_2=\dfrac{m_2\lambda D}{\dfrac{m_1\lambda D}{\beta_1}}\\\Rightarrow \beta_2=\dfrac{m_2}{m_1}\beta_1](https://tex.z-dn.net/?f=%5Cbeta_2%3D%5Cdfrac%7Bm_2%5Clambda%20D%7D%7Bd%7D%5C%5C%5CRightarrow%20%5Cbeta_2%3D%5Cdfrac%7Bm_2%5Clambda%20D%7D%7B%5Cdfrac%7Bm_1%5Clambda%20D%7D%7B%5Cbeta_1%7D%7D%5C%5C%5CRightarrow%20%5Cbeta_2%3D%5Cdfrac%7Bm_2%7D%7Bm_1%7D%5Cbeta_1)
Distance between two second order minima is given by
![y_2=2\beta_2](https://tex.z-dn.net/?f=y_2%3D2%5Cbeta_2)
![\\\Rightarrow y_2=2\dfrac{m_2}{m_1}\beta_1\\\Rightarrow y_2=2\dfrac{2}{1}\times 0.7\\\Rightarrow y_2=2.8\ cm](https://tex.z-dn.net/?f=%5C%5C%5CRightarrow%20y_2%3D2%5Cdfrac%7Bm_2%7D%7Bm_1%7D%5Cbeta_1%5C%5C%5CRightarrow%20y_2%3D2%5Cdfrac%7B2%7D%7B1%7D%5Ctimes%200.7%5C%5C%5CRightarrow%20y_2%3D2.8%5C%20cm)
The distance between the two second order minima is 2.8 cm