The answer would be C.30J
Answer:
Length, l = 3.57 meters
Explanation:
It is given that,
Area of cross-section of gold wire, 
Resistivity of gold wire, 
Resistance, R = 0.001 ohms
Resistance in terms of length and area is given by :
l = 3.57 meters
So, the length of the wire is 3.57 meters. Hence, this is the required solution.
Answer:
f = 3.102 Hz
Explanation:
In this case you have that the required voltage is the maximum induced emf produced by the rotating generator.
In order to calculate the frequency of rotation of the generator that allows one to obtain 12.0V you use the following formula:
(1)
N: turns of the armature = 95
B: magnitude of the magnetic field = 0.800T
A: area of the square armature = (9.0cm)^2 = (0.09m)^2 = 8.1*10^-3 m^2
emf_max = 12.0V
w: angular frequency
you solve the equation (1) for w:

Then, the frequency is:

Answer:
mu=12Tm^2
Explanation:
the magnetic moment mu of a single loop is given by:

where I is the current, B is the magnetic field and A is the area of the loop. By replacing we obtain:

hope this helps!!