Answer:
Required energy = 4758 J
Explanation:
Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).
Given data :
Specific heat capacity = c = 2440 J/kg.°C
Mass = m = 150 g = 0.15 kg
Initial temperature = 22°C
Final temperature = 35°C
Change in Temperature = ΔT = 13°C
Energy = E = ?
Using the following formula and substituting the values, we get:
E = m × c × ΔT
E = 0.15 × 2440 × 13
E = 4758 J
Answer:
The final velocity of cart 1 is 3m/s
Explanation:
From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.
Momentum, P is given as mass x velocity.
ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂
Assumptions:
- If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
- After the elastic collision, the two carts will move separately with different velocity
u₁ + u₂ = v₁ + v₂;
where;
u₁ and u₂ are the initial velocity for cart 1 and cart 2 respectively
v₁ and v₂ are the final velocity for cart 1 and cart 2 respectively
1 m/s + 5 m/s = v₁ + 3m/s
6 m/s = v₁ + 3m/s
v₁ = 6 m/s - 3m/s = 3m/s
Therefore, the final velocity of cart 1 is 3m/s
Sometimes, because acceleration due to gravity on Earth depends on how close you are to the Earth's center.
Answer:
382.74 kJ.
Explanation:
The work that must be done to stop an 1100 kg car travelling at 59 km/h is - 382.74 kJ.
The x-coordinates of the object at each time in a 1 ×1001 row vector named a11 using coordinate.
Coordinates are distances or angles, represented by numbers, that uniquely perceive factors on surfaces of dimensions (second) or in space of 3 dimensions.
Coordinates are hard and fast values that help to expose the exact position of a factor within the coordinated aircraft. A coordinate aircraft is a 2nd plane that's shaped by the intersection of perpendicular traces known as the x-axis and y-axis.
clear all
close all
alpha=-0.003;
w=0.05;
A=[1-alpha,-w;w,1-alpha];
A_inv=inv(A);
x0=[1;-1];
ans1=[1];
ans2=[-1];
for i=1:1000
x0=A_inv*x0;
ans1(i+1)=x0(1);
ans2(i+1)=x0(2);
end
ans1
Learn more about coordinate here:-brainly.com/question/17206319
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