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Molodets [167]
2 years ago
11

How do you write 3.32 × 10^–1 in standard form?

Mathematics
1 answer:
ikadub [295]2 years ago
8 0

Answer:

0.332

Step-by-step explanation:

just move the point to the left by the number of of power on the ten(if its negative to the left if postive to right)

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SOMEBODY HELP PLEASEEE I DONT KNOW WHY THIS IS SUPPOSED TO BE 20+ CHARACTERS LONG BUT HERE IT IS
dimaraw [331]

<u>Answer:</u>

20h + 20

<u>Step-by-step explanation:</u>

5(2h + 4) + 10h

1️⃣ Expand by distributing terms.

<em>10h + 20 + 10h</em>

2️⃣ Collect like terms.

<em>(10h + 10h) + 20</em>

3️⃣ Simplify.

<em>20h + 20</em>

Answer: <em>20h + 20</em>

Done ✔

7 0
2 years ago
Read 2 more answers
I finished question 1 but I could use some help on the others​
Eddi Din [679]

Answer:

With the first four questions, all you need to do is find a value of x that gives you a zero value in any one of those brackets.  Let's do it.

You said you finished 1, so let's skip it.

I can't give you a full answer for question 2, because you didn't capture the entire expression in the screenshot.  I can see that the values 3 and 0.125 would give zero values, but I can't tell you the last.

For question three, we need to find x values where either 9x + 3 = 0, or x² - 9 = 0.  There are three values that meet those conditions.  You can solve it just by assigning a zero value and solving for x:

9x + 3 = 0\\3x + 1 = 0\\3x = -1\\x = -1/3

For the second term actually has two solutions, because a squaring a number also causes negatives to be converted to positives.  Another way of seeing this is to notice that the second term is actually a difference of squares:

p(x) = (9x + 3)(x^2 - 9)\\= (9x + 3)(x + 3)(x - 3)

so in this case x could be -1/3, -3, or 3 to give a zero value.

For question four, you can only get a zero if you use imaginary numbers, as no real number can be squared to give you a negative.  So the only answers to that are 5i, or -5i.

With questions five six seven and eight, we just need to make exceptions for zero denominators, so:

For question 5, you can x can be any real number except -4, 2 and 7

For 6, x can be anything but 3, 1/8th or 5

for 7, We again have that difference of squares, so the actual denominator is (9x + 3)(x + 9)(x - 9), meaning x can be anything but -1/3, -9, or 9

And finally for question 8, we again have a squaring, meaning that only an imaginary number will cause division by zero, meaning x can't be 5i or -5i.

7 0
2 years ago
You roll a number cube and flip a coin. What is the probability of rolling a number less than 5 and flipping heads? Write your a
umka2103 [35]
<h2>Answer: <em><u>2/3 chance rolling less than 5 and 1/2 chance of flipping coin on heads. </u></em></h2>

<u />

Step-by-step explanation:

<h2 />

4 0
3 years ago
Points L, M, and N are collinear.
Natali5045456 [20]
<h3>Answer:</h3>

33

<h3>Step-by-step explanation:</h3>

Vocabulary

Before going into an explanation, let's go over some important vocabulary.

  • Collinear - Collinear describes points that are on the same line. This means that there is 1 line with the 3 points L, M, and N.
  • Segment addition postulate - The segment addition postulate states that if there are 2 collinear points (A and C) with another point in between them (B), then the statement AB + BC = AC must be true.

Solving for MN

Using the postulate above we can make a new equation. First, let's set up an equation that mirrors the postulate.

  • LM + LN = MN

Now, let's plug in the values we know.

  • 13 + 20 = MN

Then, solve.

  • 33 = MN

This proves that a possible value of MN is 33.

6 0
2 years ago
Please help me for my homework​
AVprozaik [17]

Answer:

49/100

Step-by-step explanation:

7 0
3 years ago
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