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Studentka2010 [4]
4 years ago
15

Jevon arrives home from school at 3:10.it takes him 15 minutes to eat a snack 1/2 hour to complete his homework 7 minutes to cha

nge clothes and pack his gear for soccer practice and 18 minutes to ride his bike to the soccer field at what time does he arrive at soccer practice
Mathematics
1 answer:
zysi [14]4 years ago
6 0
Arrives at home 3:10pm
snack 15min
homework 30min
change/pack 7min
bike ride 18min
arrives to soccer practice 4:20pm
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Can someone please help me
Salsk061 [2.6K]

Answer:

B

Step-by-step explanation:

Area of pool = l × b

l = 6x and b = 3x - 5

Area = 6x(3x - 5)

Area = 18x² - 30x

4 0
3 years ago
Everbank Field, home of the Jacksonville Jaguars, is capable of seating 76,867 fans. The revenue for a particular game can be mo
Andrei [34K]
The domain of the function is all the values from which the functio can be mapped: here it's between 0 and <span>76,867 -depending on how many people come

</span>0 \leq x\geq 76867

The range is all the values that the function can have.So here it's from 0, when noone is coming, to 76867*161=12377036

0 \leq y\geq 12377036




5 0
3 years ago
Please simplify I need the extra credit all answers get brainiest.
antoniya [11.8K]

Answer:

3/10a^15b^7c^4

Step-by-step explanation:

sorry its kinna hard to explain

8 0
3 years ago
Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim
sergejj [24]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958      

c) p_v =P(t_{34}>2.958)=0.0028    

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

The sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=17 represent the sample mean    

s=4 represent the sample standard deviation

n=35 sample size  

\mu_o =15 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

Since we don't  know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958  

Part c P-value  

The degrees of freedom are given by:

df = n-1= 35-1=34

Since is a right tailed test the p value would be:  

p_v =P(t_{34}>2.958)=0.0028  

Part d Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

7 0
3 years ago
Can someone please help with these
nataly862011 [7]

3. The simplest form of √42 is √42


4. √75

Rewrite 75 as 5^2 * 3

Now you have √(5^2*3)

Pull squared terms out from the radical to get 5√3

3 0
3 years ago
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