F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
Answer:
a) The arithmetic sequence with common difference 2 that has 8 as the first term.
b) The arithmetic sequence of common difference -5 and first term 15.
Step-by-step explanation:
Let's use for example the arithmetic sequence with common difference 2 that has 8 as the first term. Then the first two terms of this sequence are:
8, and (8+2) = 10 Therefore the second term is 10.
Another arithmetic sequence of common difference -5 and first term 15. The firs two terms of this sequence are:
15, and (15 - 5) = 10. Therefore again a 10 as second term.
Answer:
It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0
Explanation:
We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:
Let's start with the roots:
x=3, x=−4
So let's move the constants over with the x terms to have equations equal to 0:
x−3=0, x+4=0
Now we can set up the equation, as:
(x−3)(x+4)=0
We can now distribute out the 2 quantities:
x2+x−12=0
Answer:
Step-by-step explanation:
Since the squares have areas of 32u^2. The side lengths are

Answer:
Does February March?.... NO, but APRIL MAY
Step-by-step explanation:
Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
\Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY
Does February March?.... NO, but APRIL MAY