A room has an area of 60 sq meters and a perimeter of 32 meters. What is the length and width

8) "Sweet' and 'pungent are

pashok25 [27]

Answer:

antonyms?

Step-by-step explanation:

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=1%2B2x%3D4x%2B9" id="TexFormula1" title="1+2x=4x+9" alt="1+2x=4x+9" align="absmiddle" class="l

kicyunya [14]

Answer:

x= -4

Step-by-step explanation:

=> 1+2x= 4x+9

=> 1-9=4x-2x

=> -8 = 2x

=> x = -8/2

=> x= -4

hope it's helpful to you ☺️

6 0

3 years ago

Read 2 more answers

Are -2x + 9 = 7 and 2x = 2 equivalent?

DochEvi [55]

Answer:

Yes because the answer to both of them is 1

Step-by-step explanation:

Let's solve your equation step-by-step.

−2x+9=7

Step 1: Subtract 9 from both sides.

−2x+9−9=7−9

−2x=−2

Step 2: Divide both sides by -2.

−2x

−2

=

−2

x=1

Answer:

x=1

Let's solve your equation step-by-step.

2x=2

Step 1: Divide both sides by 2.

2x

2

=

2

x=1

Answer:

x=1

7 0

3 years ago

1. Ms. Geyer wants to take personal training classes at a nearby gym but needs to start by selecting a membership plan.

Triss [41]

Mrs geyer is gonna have to get a new membership to the gym which is 60$ of ever day

5 0

2 years ago

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

3 years ago