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2 years ago

If P = 4x^4 - 3x^3 + x² - 5x + 11 and Q = -3x^4 + 6x^3 - 8x² + 4x - 3, what is P - 2Q?

Mathematics

1 answer:

vazorg [7]2 years ago

7 0

Answer:

10x^4-15x^3+17x^2-13x+17

Step-by-step explanation:

P-2Q

Replace P and Q with the given values,

4x^4-3x^3+x^2-5x+11-(2(-3x^4+6x^3-8x^2+4x-3)

4x^4-3x^3+x^2-5x+11-(-6x^4+12x^3-16x^2+8x-6)

4x^4-3x^3+x^2-5x+11+6x^4-12x^3+16x^2-8x+6

10x^4-15x^3+17x^2-13x+17

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A recent study focused on the number of times men and women send a Twitter message in a day. The information is summarized below

jok3333 [9.3K]

Answer:

The value of the test statistic = 2.58

Test statistic Z = - 4.805

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

There is significant difference between in the mean number of times men and women send a Twitter message in a day

Step-by-step explanation:

Step(i):-

Sample size of men n₁ = 25

mean of the first sample x₁⁻ = 20

Standard deviation of the first sample σ₁ = 5

Sample size of women n₂ = 30

mean of the second sample x₂⁻ = 30

Standard deviation of the first sample σ₂ = 10

Level of significance ∝= 0.01

Step(ii):-

Null Hypothesis : H₀: There is no significant difference between in the mean number of times men and women send a Twitter message in a day

Alternative Hypothesis :H₁:There is significant difference between in the mean number of times men and women send a Twitter message in a day

Test statistic

$Z = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S.D_{1} ^{2} }{n_{1} }+\frac{ S.D_{2} ^{2}}{n_{2} } } }$

$Z = \frac{20 - 30 }{\sqrt{\frac{(5)^{2} }{25 }+\frac{ (10)^{2} }{ 30} } }$

Z = $\frac{-10}{2.081} = - 4.805$

The value of the test statistic = 2.58 C

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

Conclusion:-

There is significant difference between in the mean number of times men and women send a Twitter message in a day

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Answer:

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Step-by-step explanation:

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n is term number

Step 1: Find common ratio r

r = 10/2 = 5

Step 2: Plug variables into formula

$a_n = 2(5)^{n-1}$

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