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Tanzania [10]
2 years ago
5

If P = 4x^4 - 3x^3 + x² - 5x + 11 and Q = -3x^4 + 6x^3 - 8x² + 4x - 3, what is P - 2Q?

Mathematics
1 answer:
vazorg [7]2 years ago
7 0

Answer:

10x^4-15x^3+17x^2-13x+17

Step-by-step explanation:

P-2Q

Replace P and Q with the given values,

4x^4-3x^3+x^2-5x+11-(2(-3x^4+6x^3-8x^2+4x-3)

4x^4-3x^3+x^2-5x+11-(-6x^4+12x^3-16x^2+8x-6)

4x^4-3x^3+x^2-5x+11+6x^4-12x^3+16x^2-8x+6

10x^4-15x^3+17x^2-13x+17

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MatroZZZ [7]

Answer:

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Step-by-step explanation:

Substitute the value of x given in f(x) into the equation f(x) = 8x^2 - 7x + 3

For example, f(0) would be f(0) = 8(0)^2 - 7(0) + 3.  f(0) = 3

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                                = 32 + 17        therefore      f(-2) = 49

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2 years ago
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Answer:


Step-by-step explanation:

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Step-by-step explanation:

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