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zmey [24]
3 years ago
7

Which of the following is the formula used to calculate the variance of a set of data

Mathematics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

he's right, the answer is a

Step-by-step explanation:

den301095 [7]3 years ago
6 0

Answer:

(A) s^{2}=\frac{1}{n-1}\sum_{i}^{n}(x_{i}-\bar{x})^{2}

Step-by-step explanation:

Variance is the expectation of the squared deviation from the mean of x. Variance of the set of data can be discrete, continuous or mixed.

In order to calculate the variance of the set of the provided data, we need x_{i}= Terms in set of data,

\bar{x}= Sample mean

∑= sum,

n= sample size.

The variance can be calculated as:

s^{2}=\frac{1}{n-1}\sum_{i}^{n}(x_{i}-\bar{x})^{2}

where s^{2} is the variance and is always measured in squared units.

The correct formula is option (A),since it consists of summation of the square of the difference of the terms in the data and the mean, also variance is the measure of how far is each value in the given data from the mean, which is the correct formulation of the variance.



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Salsk061 [2.6K]
Look at the picture
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6 0
3 years ago
Solve for a. Show your work (ALL steps must be shown): -2(a-3)=12
irga5000 [103]

Answer

a= -6

Step-by-step explanation:

-2(a-3)=12

1.) -2(a)= -2a

2) -2(-3)= 6

3)  -2a+6=12

          -6    -6

4) -2a/-2 = 12/-2

a = -6

3 0
3 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
There are 45 students who play a woodwind instrument in the school band. Of these, 18 play the saxophone. What percent of these
Mashutka [201]

Answer:

40% students play the saxophone.

Step-by-step explanation:

Given:

Total Number of students who play woodwind instrument = 45

Number of students who play saxophone = 18

We need to find the percent of students who play saxophone.

Solution:

Now we can say that;

To find the percent of students who play saxophone we will divide Number of students who play saxophone by Total Number of students who play woodwind instrument and the multiply by 100.

framing in equation form we get;

percent of students who play saxophone = \frac{18}{45}\times100= 40\%

Hence 40% students play the saxophone.

3 0
3 years ago
I WILL MARK BRAINIEST IF CORRECT!
Lunna [17]

Answer:

I believe I would be the last one D

8 0
3 years ago
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