The first one is 64. The second one is -64. Third is 10000
Answer:
oNE DAY A TRIANGLE SPLIT IN SO MANY DIFFERENT PEICES VBUT SUDDENLY ONE DAY THEY ALL CAME BACK.....
Step-by-step explanation:
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Fter<span> a </span>125<span>% </span>markup<span> and a </span>10<span>% </span>discount<span> the </span>price<span> of a </span>watch<span> is 30.78 </span>before tax<span> what was the </span>wholesale price<span> - 2929721. ... If an item is $15.20 is increased by </span>125<span>% (34.20) it would be about $34.20 </span>before<span> we subtract </span>10<span>% (3.42)....we arrive at the end </span>cost<span> of </span>$30.78<span>. </span>wholesale price<span>would be 15.20.</span>
