(3^2)=9
(3^3)=27
(2^3)=8
9 times 27 times 8 = 1944
The answer is C.) A+2/5B.
Adding equation A to 2/5B will result in canceling the x terms, i.e. 2/5x + 2/5(-x) = 0.
<h3>
Answer: 80</h3>
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Explanation:
We'll need to find the LCM of 5, 8 and 10.
List out the prime factorization of the three numbers.
The unique prime factors are 2 and 5. The '1' isn't a prime number, so we can ignore it.
The '2' has an exponent of 3 as the largest exponent, meaning 2^3 is part of the LCM. The '5' has the largest exponent of 1. So 5^1 = 5 is also part of the LCM
LCM = 2^3*5 = 8*5 = 40
List out the multiples of 40
40, 80, 120, 160, ...
The number <u>80</u> is the only multiple between 61 and 107