Answer:
(x + 4)(x – 8)
Step-by-step explanation:
1. (x – 16)(x + 2)
x² - 2x - 16x - 32
x² - 18x - 32
2. (x + 2)(x – 16)
x² - 16x + 2x - 32
x² - 14x - 32
3. (2 – )(x + 4)
2x + 8
4. (x + 8)(x – 4)
x² - 4x + 8x - 32
x² + 4x - 32
5. (x + 4)(x – 8)
x² - 8x + 4x - 32
x² - 4x - 32
6. (x – 4)(x+8)
x² + 8x - 4x - 32
x² + 4x - 32
Let
x------> <span>speed on the bicycle
y------> </span><span>speed walking
we know that
</span>x=6+y------> equation 1<span>
speed=distance /time-------> time=distance/speed
1/y=2.5/x-------> y=x/2.5------> x=2.5y-------> equation 2
equals 1 and 2
6+y=2.5y-----> 2.5y-y=6------> 1.5y=6-----> y=6/1.5-----> y=4 mi/h
x=6+y-----> x=6+4-----> x=10 mi/h
the answer is
the speed walking is 4 mi/h
</span><span>
</span>
Answer:
A. 0.0001
Step-by-step explanation:
z-statistic:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
In this question:
The value of the z-statistic is z = 3.74.
The desired probability is 1 subtracted by the pvalue of z = 3.74.
z = 3.74 has a pvalue of 0.9999
Then
1 - 0.9999 = 0.0001.
So the correct answer is given by option A.
Answer:
Step-by-step explanation:
Given the following lengths AB = 64, AM = 4x + 4 and BM= 6x-10, If M lies on the line AB then AM+MB = AB (addition property)
Substituting the given parameters into the addition property above;
AM+MB = AB
4x + 4 + 6x - 10 = 64
combine like terms
4x+6x = 64+10-4
10x = 74-4
10x = 70
Divide both sides by 10
x = 70/10
x = 7
Note that for M to be the midpoint of AB then AM must be equal to BM i.e AM = BM
To get AM ;
Since AM = 4x+4
substitute x = 7 into the function
AM = 4(7)+4
AM = 28+4
AM = 32
Similarly, BM = 6x-10
BM = 6(7)-10
BM = 42-10
BM = 32
<em></em>
<em>Since AM = BM = 32,. then M is the midpoint of AB</em>
