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ale4655 [162]
3 years ago
12

Joseph is standing 12 feet from a mirror lying on the ground, and his eyes are 5 feet above the ground. The line-of-sight reflec

tions on the mirror makes mc003-2.jpg congruent to mc003-3.jpg . If the building is 264 feet from the mirror, which is closest to the height of the building?

Mathematics
1 answer:
eimsori [14]3 years ago
8 0
See the attached figure which represents the explanation of the problem.
Let <span>the height of the building = h
</span>
∵ ∠1 congruent to ∠2
∴ ∠1 = ∠2
∴ tan (∠1) = tan (∠2)    ⇒⇒⇒  tan of the angle =  (opposite/adjacent)

∴ \frac{5}{12} =  \frac{h}{264}
∴ 12 h = 5 * 264 = 1,320
∴ h = 1,320/12 = 110 feet

∴ T<span>he height of the building = 110 feet
</span>

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