Ask question

Ask question

All categories

3 years ago

15

At STP, the element oxygen can exist as either O2 or O3 gas molecules. These two forms of the element have (1) the same chemical

and physical properties (2) the same chemical properties and different physical properties (3) different chemical properties and the same physical properties (4) different chemical and physical properties

1 answer:

Oduvanchick [21]3 years ago

6 0

Answer:

O2 and O3 are allotropes of Oxygen, therefore they have (4) different chemical and physical properties.

Explanation:

You might be interested in

What is the acceleration of a 50 kg object pushed with a force of 500 newtons?

son4ous [18]

Answer:

F = MA

500 = 50 multiply by A

A= 500/50

A= 10m/s2

3 0

2 years ago

Use the given data at 500 K to calculate ΔG°for the reaction

Anton [14]

Answer : The value of $\Delta G^o$ for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

$2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)$

First we have to calculate the enthalpy of reaction $(\Delta H^o)$ .

$\Delta H^o=H_f_{product}-H_f_{reactant}$

$\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]$

where,

$\Delta H^o$ = enthalpy of reaction = ?

n = number of moles

$\Delta H_f^0$ = standard enthalpy of formation

Now put all the given values in this expression, we get:

$\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]$

$\Delta H^o=-1035.6kJ=-1035600J$

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction $(\Delta S^o)$ .

$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]$

where,

$\Delta S^o$ = entropy of reaction = ?

n = number of moles

$\Delta S_f^0$ = standard entropy of formation

Now put all the given values in this expression, we get:

$\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]$

$\Delta S^o=-153J/K$

Now we have to calculate the Gibbs free energy of reaction $(\Delta G^o)$ .

As we know that,

$\Delta G^o=\Delta H^o-T\Delta S^o$

At room temperature, the temperature is 500 K.

$\Delta G^o=(-1035600J)-(500K\times -153J/K)$

$\Delta G^o=-959100J=-959.1kJ$

Therefore, the value of $\Delta G^o$ for the reaction is -959.1 kJ

3 0

2 years ago

During oxidation, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g

EastWind [94]

Oxidation is when the overall charge (or oxidation number) increases. The only way to increase an oxidation number is to lose an electron, thereby making the negative charges less. The correct answer is C.

6 0

3 years ago

Read 2 more answers

How much does the universe(galaxy) weigh?

AfilCa [17]

Answer:

(before researching)it weighs a positive infinity ∞

Explanation:

(after researching)Our galaxy weighs in at around 10^42 kilograms and the entire visible universe reaches something like 10^53. You can try to convert those figures to something a little more familiar, such as the weight of a blue whale, by subtracting 5 from any of those exponents.

hope this helps have a great day also brainly would be very much appreciated

and here's a meme

7 0

2 years ago

Read 2 more answers

ILL GIVE BRAINLIST IF YOU GET IT RIGHT Which of the following is an example of gravitational potential energy?

FinnZ [79.3K]

A glass jar sitting on a shelf.

If the shelf gets tipped the jar will slide off and convert to kinetic energy as gravity pulls it to land on the next level/floor

6 0

2 years ago