ALGEBRA SECTION 3 TEST YOURSELF <br>PLEASE I NEED HELP ASAP RIGHT NOW PLEASE

Pls help i only have a couple mins left to finish, i need help with both 1 and 2

babunello [35]

First one is 2 and last one is -1/3. Hope this helps :P

8 0

3 years ago

The lines graphed below are parallel.the slope of the slope of red line is 2/5 .what is the slope of the green line

Yuliya22 [10]

Answer:

$\large\boxed{\text{the sloe}\ m=\dfrac{2}{3}}$

Step-by-step explanation:

$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \parallel\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

$\text{We have the slope}\ m_1=\dfrac{2}{5}.\\\\\text{The slope of parallel line is the same:}\ m_2=\dfrac{2}{5}$

8 0

4 years ago

Determine whether each equation is True or False. In case you find a "False" equation, explain why is False.

elixir [45]

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) $\sqrt{32} = 2^{\frac{5}{2} }$

$2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ = \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}$

Thus, the equation is TRUE.

(2) $16^{\frac{3}{8} } = 8^2$

$16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64$

Thus, the equation is FALSE.

(3) $4^{\frac{1}{2} } = \sqrt[4]{64}$

$4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64} = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2} \times \sqrt{2} \times \sqrt{2} ) = 2\sqrt{2}$

Thus, the equation is FALSE.

(4) $2^8 = (\sqrt[3]{16} )^6$

$2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256$

Thus, the equation is TRUE.

(5) $(\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\$

$8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4$

Thus, the equation is FALSE.

4 0

3 years ago

Identify whether the following items best fit with a discrete or a continuous model. Then determine whether it is a linear (arit

astra-53 [7]

Answer:

it will be a continuous model

Step-by-step explanation:

weekend weekend assume every amount of area infected by the bed period doubles as hour passes

5 0

3 years ago

What is the equation of a line that has a slope of 3 and a y-intercept of -3

LUCKY_DIMON [66]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

We have m = 3 and b = -3. Substitute:

6 0

3 years ago

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ALGEBRA SECTION 3 TEST YOURSELF PLEASE I NEED HELP ASAP RIGHT NOW PLEASE