Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Answer:
35 cones
Step-by-step explanation:
21 x $2.50
=52.5
52.5/$1.50
= 35 small cones he can buy
B. 24 square meters. Length times width times height
0.84(20)=$16.80
700/100=7
7(1.02)=$7.14
$7.14+16.80=$23.94 in total
He lost $30 bc
Guy stole $100
Guy gave back $70
Owner gives hue $30 !
If that makes any sense ♀️
