Question

In a quadrilateral MNOP the length of side MN is (4x − 7) units and the length of side ON is (7 − 3x) units. What value of x will make it a rhombus?
14
2
7
12

Answer 1

In a rhombus, all sides are equal.

So for the quadrilateral MNOP to be a rhombus, the given sides have to be equal. THat is

$MN=ON$

$4x-7 =7-3x$

Adding 3x to both sides and addinf 7 to both sides

$7x = 14$

Now we need to get rid of 7 and for that we do division, that is

$\frac{7x}{7} = \frac{14}{7}$

$x=2$

Correct option is the second option .