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3 years ago

Practice worksheet : relations and functions

Mathematics

2 answers:

jenyasd209 [6]3 years ago

7 0

Answer:b

Step-by-step explanation:

ololo11 [35]3 years ago

6 0

Where is the work sheet and I will see what I can do.

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1. 5 less than one fourth of x is y.

horsena [70]

Answer

y = (1/4)x - 5 or 4y - x + 20 = 0

Explanation

To get the rule required, we interpret the sentence and write it in a mathematical form.

5 less than one fourth of x is y

one fourth of x ⇒ (1/4)x

5 less than one fourth of x is y ⇒ (1/4)x - 5 = y

y = (1/4)x - 5

4y = x - 20

4y - x + 20 = 0

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3 years ago

What is the value of x in the equation 3x - 4y=65, when y=4?<br> N

4vir4ik [10]

Answer:

x =27

Step-by-step explanation:

3x - 4y=65

lets substitute the value of y in the equation:

3x -4(4) =65

3x = 65 +16

3x= 81

x= 81/3

x = 27

3 0

3 years ago

Write the equation of a line with slope 3 and y-intercept −3.

natta225 [31]

The equation would be y = 3x-3

4 0

3 years ago

Read 2 more answers

Let A(t) be the area of a circle with radius r(t), at time t in min. Suppose the radius is changing at the rate of drdt=6 ft/min

mylen [45]

Answer:

The rate of change is $108\pi$ ft^(2)/min

Step-by-step explanation:

The area of a circle is given by the following equation:

$A(t) = \pi r^{2}$

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

$\frac{dA(t)}{dt} = 2\pi r \frac{dr}{dt}$

We have that:

$\frac{dr}{dt} = 6, r = 9$ .

We want to find $\frac{dA}{dt}$

$\frac{dA(t)}{dt} = 2\pi*9*6$

$\frac{dA}{dt} = 108\pi$

Since the area is in square feet, the rate of change is in ft^(2)/min.

So the rate of change is $108\pi$ ft^(2)/min

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3 years ago

Which graph represents as a function of length of the trip

Sav [38]

Do you have a picture to go with it?

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3 years ago