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3 years ago

M : ___ b : _ Equation : ____ PLEASE HELP ME !!!

Mathematics

1 answer:

fredd [130]3 years ago

6 0

Answer:are you saying mx+b

Step-by-step explanation: hopefully that helps you mark me brainlest please

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Trying to understand this question

Varvara68 [4.7K]

Answer:

option 2 I think sorry if its incorrect

5 0

3 years ago

What is the length of missing side JK? Round Answer to nearest tenth please.

zvonat [6]

Given:

Triangle LJK.

LJ = 89 in, LK = 28 in and m∠L = 42°

To find:

The length of missing side JK.

Solution:

LJ = k = 89

LK = j = 28

JK = l = ?

Using law of cosine:

$l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L$

Substitute the given values.

$l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ$

$l^{2}=784+7921-4984 \cdot (0.7)$

$l^{2}=784+7921-4984 \cdot (0.7431)$

$l^{2}=784+7921-3703.6$

$l^{2}=5001.4$

Taking square root on both sides.

$l=70.7$

The length of the missing side is 70.7 in.

4 0

3 years ago

Suda çözündüklerinde H* iyonu verebilen

Afina-wow [57]

Answer:

u just need to pute it right

7 0

3 years ago

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran

mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

$X=48$ number of vehicles classified as sports utility.

$n=500$ random sample taken

$\hat p=\frac{48}{500}=0.096$ estimated proportion of vehicles classified as sports utility vehicles.

$p$ true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070$

$0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121$

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

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3 years ago

Does this graph represent a function?Why or why not?

cestrela7 [59]

No, it does not have a straight line. (A)

4 0

3 years ago

Read 2 more answers

M : _____ b : _____ Equation : ______ PLEASE HELP ME !!!

M : ___ b : _ Equation : ____ PLEASE HELP ME !!!