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Vlada [557]
3 years ago
10

Special right triangles

Mathematics
1 answer:
Korolek [52]3 years ago
5 0

Answer:

see down

Step-by-step explanation:

cos 60 = \frac{x}{6\sqrt{3} } \\x = 6\sqrt{3}  *  cos60\\x = 6\sqrt{3} * \frac{1}{2}  \\x = 3\sqrt{3}

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Use pascal's triangle to expand the binomial<br> (d-5y)^6<br><br> please show work
Ratling [72]
Pascals triangle to the 6th:
1                                     x^0
1 1                                  x^1
1 2 1                               x^2
1 3 3 1                           x^3
1 4 6 4 1                        x^4
1 5 10 10 5 1                x^5
1 6 15 20 15 6 1          x^6<span>

</span>the problem is to the 6th power so your going to use the 6th row of pascals triangle (don't count the first row). these numbers represent the coefficients of the variables

1(d-5y)^6 + 6(d-5y)^5 + 15(d-5y)^4 + 20(d-5y)^3 + 15(d-5y)^2 + 6(d-5y) + 1
then simplify

4 0
3 years ago
Read 2 more answers
Help<br> PleSe due now!!!!!
AveGali [126]

Answer:

1/2

Step-by-step explanation:

3/6 = 1/2

3 0
3 years ago
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What is the product of 710 and 323?<br><br> 135<br><br> 11315<br><br> 21730<br><br> 3715
Firlakuza [10]

Answer:

I think I answer is 21730 I'm not sure tho

3 0
3 years ago
Put the following in order from the smallest to the largest 0.2 1/2 2%
aliya0001 [1]

Answer:

2%, 0.2, 1/2

Step-by-step explanation:

0.2 = 0.20 = 20%

1/2 = 0.50 = 50%

2% = 0.02

3 0
3 years ago
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Find the solution to the equation below.
Andreyy89

Answer:

B and D

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=20, b=-26, and c=8.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{26+/-\sqrt{26^2-4(20)(8)} }{2(20)}=\frac{26+/-\sqrt{676-640} }{40)}

\frac{26+/-\sqrt{36} }{40}=\frac{26+/-6 }{40}

This means the solutions are 26 - 6/ 40 and 26 + 6/ 40.

It simplifies to 1/2 and 4/5.

3 0
3 years ago
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