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2 years ago

Can Someone Help With This Question Please

Mathematics

2 answers:

8090 [49]2 years ago

8 0

4x²+x³

Factor is out x³ expression

The answer is :

${x}^{2} \times (4 + 3x)$

Carry learning!

Dovator [93]2 years ago

7 0

<h3><u>Given </u><u>:</u><u>-</u></h3>

We have given expression, 4x² + x³

We have to factorise this expressions as fully as possible

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

4x² + x³

Arrange it accordingly

x³ + 4x²

X is common in the expression

x²( x + 4 )

x² ( 4 + x)

Hence, After factorization we got two possible factors of the above expression that is x² and (4 + x )

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Identify the maximum or minimum value and the domain and range of the graph of the function y = 2(x – 3)2 – 4.

NISA [10]

We are given the equation y = 2(x – 3)^2 – 4 and is asked for the domain and range of the following function. In this case, there is no radical sign so the domain includes all real numbers. The range has a minimum value of -4 since the squaring makes the value on the first term positive. Hence the answer is A.

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3 years ago

Can i get help working out 3x− 12 = 2x+ 3

Naddik [55]

Answer:

x = 15

Step-by-step explanation:

3x− 12 = 2x+ 3

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2 years ago

\(x + 60)<br> Find mZGJI<br> A. 15°<br> B. 75°<br> C. 100°<br> D. 1050

vampirchik [111]

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Step-by-step explanation:

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3 years ago

An article in The Engineer (Redesign for Suspect Wiring," June 1990) reported the results of an investigation into wiring errors

GarryVolchara [31]

Answer:

a) The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b) A sample of 408 is required.

c) A sample of 20465 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Of 1600 randomly selected aircraft, eight were found to have wiring errors that could display incorrect information to the flight crew.

This means that $n = 1600, \pi = \frac{8}{1600} = 0.005$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 - 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0005$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 + 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0095$

The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b. Suppose we use the information in this example to provide a preliminary estimate of p. How large a sample would be required to produce an estimate of p that we are 99% confident differs from the true value by at most 0.009?

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A sample of n is required, and n is found for M = 0.009. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.009 = 2.575\sqrt{\frac{0.005*0.995}{n}}$

$0.009\sqrt{n} = 2.575\sqrt{0.005*0.995}$

$\sqrt{n} = \frac{2.575\sqrt{0.005*0.995}}{0.009}$

$(\sqrt{n})^2 = (\frac{2.575\sqrt{0.005*0.995}}{0.009})^2$

$n = 407.3$

Rounding up:

A sample of 408 is required.

c. Suppose we did not have a preliminary estimate of p. How large a sample would be required if we wanted to be at least 99% confident that the sample proportion differs from the true proportion by at most 0.009 regardless of the true value of p?

Since we have no estimate, we use $\pi = 0.5$