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zhuklara [117]
3 years ago
9

What si the name of the state change water is going through as it boils?

Physics
1 answer:
Blababa [14]3 years ago
3 0
It evaporates into a vapor

  ~~~hope this helps~~~
~~have a beautiful day~~
            ~davatar~
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Mkey [24]
I believe the answer is B. let me know If I was right.
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3 years ago
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How many neutrons are in the nucleus of an atom with an atomic mass of 80 A.M.U. and an atomic number of 35?
belka [17]

Answer:

45

Explanation:

The mass number is 80

Proton number is 35

A-P=n

80-35=45

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3 years ago
An object of mass m is dropped from height h above a planet of mass M and radius R .
Margarita [4]

Answer:

v = \sqrt{2GM(\frac{1}{R+h)}-\frac{1}{R})}

Explanation:

The initial mechanical energy of the object, when it is located at height h above the the planet, is just gravitational potential energy:

E=U=\frac{GMm}{(R+h)}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the object

R is the radius of the planet

h is the altitude of the object

When the object hits the ground, its mechanical energy will sum of potential energy and kinetic energy:

E=\frac{GMm}{R}+\frac{1}{2}mv^2

where

v is the speed of the object at the ground

Since the mechanical energy is conserved, we can write

\frac{GMm}{R}+\frac{1}{2}mv^2=\frac{GMm}{R+h}

and solving for v, we find

\frac{GMm}{R}+\frac{1}{2}mv^2=\frac{GMm}{R+h}\\v = \sqrt{2GM(\frac{1}{R+h)}-\frac{1}{R})}

3 0
3 years ago
What is the transfer of heat through flowing material
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A playground slide is 8.80 ft long and makes an angle of 25.0° with the horizontal. A 63.0-kg child, initially at the top, slide
mario62 [17]

Answer:

initial: 1654.6 J, final: 0 J, change: -1654.6 J

Explanation:

The length of the slide is

L = 8.80 ft = 2.68 m

So the height of the child when he is at the top of the slide is (with respect to the ground)

h = L sin \theta = (2.68 m)sin 25.0^{\circ}=1.13 m

The potential energy of the child at the top is given by:

U = mgh

where

m = 63.0 kg is the mass of the child

g = 9.8 m/s^2 is the acceleration due to gravity

h = 1.13 m

Substituting,

U=(63.0 kg)(9.8 m/s^2)(2.68 m)=1654.6 J

At the bottom instead, the height is zero:

h = 0

So the potential energy is also zero: U = 0 J.

This means that the change in potential energy as the child slides down is

\Delta U = 0 J - (1654.6 J) = -1654.6 J

7 0
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